The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?
1 answer:
Solve for k for each value of the range, and you will obtain each value of k that may belong to the domain
1) k^2 +2k +1 = 25
k^2 + 2k -24 = 0
(k + 6)(k- 4) = 0
k + 6 = 0 ⇒ k = - 6
k - 4 = 0 ⇒ k = 4
2) k^2 + 2k + 1 = 64
k^2 + 2k - 63 = 0
(k + 9)(k - 7) = 0
k + 9 = 0 ⇒ k = -9
k - 7 = 0 ⇒ k = 7
Then the largest possible domain is {-9, -6, 4, 7}
You might exclude one from -6 and 4 but not both.
You might also exclude one from -9 and 7 but not both
Because with those sets you will obtain all the images that are in the range.
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Answer:
x=4. Verified, Not wrong.
Step-by-step explanation:
24=9x+4-4x
24 = 5x+4
20-4
5x=20
(divide)
x=4
Answer:
x + Y = 39 or x = 39-y
20x + 50y = 1.40
20 (39 - y) + 50y = 11.40
7.80 - 20y + 50y = 11.40
30y = 11.40 - 7.80
30y = 3.60
y = 3.60/30
y = 12 50p coins were collected.
x = 39 - 12 = 27 20p coins were collected.
Proof:
20*27 + 50*12 = 11.40
5.40 + 6 = 11.40
11.40 = 11.40
I hope it helps.
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