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Mila [183]
3 years ago
8

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0
Solve for k for each value of the range, and you will obtain each value of k that may belong to the domain

1) k^2 +2k +1 = 25

k^2 + 2k -24 = 0

(k + 6)(k- 4) = 0
k + 6 = 0 ⇒ k = - 6

k - 4 = 0 ⇒ k = 4

2) k^2 + 2k + 1 = 64

k^2 + 2k - 63 = 0

(k +  9)(k -  7) = 0

k + 9 = 0 ⇒ k = -9
k - 7 = 0 ⇒ k = 7

Then the largest possible domain is {-9, -6, 4, 7}

You might exclude one from -6 and 4 but not both.

You might also exclude one from -9 and 7 but not both

Because with those sets you will obtain all the images that are in the range.

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Which expressions are equivalent to –9<br> (2/3x+1)? Check all that apply.
Degger [83]

Answer:

-18/3x - 9

Step-by-step explanation:

-9(2/3x + 1)

Expand.

-18/3x + -9

4 0
3 years ago
Someone help I don't know what the diameter or radius is​
Elenna [48]
<h3><u>Answer:</u></h3>

52.38 inch² & 261.90 inch²

<h3><u>Step-by-step explanation:</u></h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3><u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>

\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}

\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}

5 0
3 years ago
Factor the polynomial 4x4 – 20x2 – 3x2 + 15 by grouping. What is the resulting expression?
siniylev [52]

Factoring the polynomial 4x^4-20x^2-3x^2 + 15 by grouping means separation of the polynomial in two addends, each of them consists of two addends:

4x^4-20x^2-3x^2 + 15=(4x^4-20x^2)+(-3x^2+15).

In first brackets the common factor is 4x^2, in second brackets the common factor is -3.

Then

(4x^4-20x^2)+(-3x^2+15)=4x^2(x^2-5)-3(x^2-5)=(x^2-5)(4x^2-3).

Answer: correct choice is B

7 0
4 years ago
Read 2 more answers
HELP !!! | 20 Points.
RUDIKE [14]

Answer:

No. The ladder is too steep.

Step-by-step explanation:

Length of ladder = 17 feet.  This is the hypotenuse.

Side a of a right triangle = 16.6

To answer this, you need one of the trigonometric functions.  

Opposite = 16.5

hypotenuse = 17

The function you need is the sine function.

Sin(theta) = opposite / hypotenuse

sin(theta) = 16.5 / 17

Sin(theta) = 0.97059

theta = sin-1(0.07059)

theta = 76.07

No the ladder is too steep.

5 0
3 years ago
Read 2 more answers
James bought a cake that weighs 3 1/4 pounds how many ounces does the cake weigh?
Dima020 [189]
[16 ounces = 1 pound]
8 0
3 years ago
Read 2 more answers
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