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Liono4ka [1.6K]
3 years ago
6

PLS HELP GIVING 100 POINTS TO THE PERSON WHO WRITES IT

Computers and Technology
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

The HR HEAD

XYZ COMPANY

Baltimore

United States

Dated: December 19th, 2019

Subject: To apply for an internship in your esteemed XYZ Software development company

Respected Sir,

I am in the final year of my engineering, and my specialization is Information technology.

Being an IT student, I am quite good at organizing as well as filing the office materials. I have expertise by now in project management as well, and I can prepare any form of software project documents, project schedules, or any form of software project management reports. I am proficient in communication as well and write as well as send any type of email. I can perform any kind of communications task. I can participate as well as take note of any kind of team meetings as well as observe and capture details of the interaction with any sort of client with the same intent. I am at first an IT Expert and hence can enter any length of data into any software on computer systems. Also, I can work quite effectively on any operating system, and on both Mac OS and Windows PC. I also have the required know-how of computer hardware just in case it is required. I have a very deep interest in technology, and can quite effectively use the word processing programs, and do an extensive research on any topic or any sort of search and findings on internet.

Kindly please grant me an opportunity to work as an intern in your esteemed company.

Yours amicably,

XYZ

ABC University

DEF State

United States    

Explanation:

The Answer is self explanatory.

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Answer:

Proved

Explanation:

Given

X = (a.\bar b)+(\bar a.b)

(a + b)\ .  \frac{}{a.b}

Required

Find out why they represent the same

To do this, we simplify either (a + b)\ .  \frac{}{a.b} or X = (a.\bar b)+(\bar a.b)

In this question, I will simplify (a + b)\ .  \frac{}{a.b}

Apply de morgan's law

(a + b)\ .  \frac{}{a.b} = (a + b) . (\bar a + \bar b)

Apply distribution property

(a + b)\ .  \frac{}{a.b} = a.\bar a + a.\bar b + \bar a . b + b . \bar b

To simplify, we apply the following rules:

a.\bar a = 0 --- Inverse law

b.\bar b = 0 --- Inverse law

So, the expression becomes

(a + b)\ .  \frac{}{a.b} = 0 + a.\bar b + \bar a.b + 0

(a + b)\ .  \frac{}{a.b}  = a.\bar b + \bar a.b

Rewrite as:

(a + b)\ .  \frac{}{a.b}  = (a.\bar b)+(\bar a.b)

From the given parameters:

X = (a.\bar b)+(\bar a.b)

This implies that:

(a + b)\ .  \frac{}{a.b} when simplified is X or (a.\bar b)+(\bar a.b)

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