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elena55 [62]
3 years ago
8

Every fourth customer gets a free calendar. Every sixth customer gets a coupon for $1 off his or her meal. Which customer will b

e the first one to to get both the calendar and the coupon?
Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0
It would be the 12th customer
You might be interested in
Analyze the table below and answer the question that follows.
lora16 [44]

Answer:

C. Events E and A are independent

Step-by-step explanation:

we will verify each options

(a)

We can use independent events formula

P(B∩C)=P(B)*P(C)

we are given

P(B)=0.4

P(C)=0.25

P(B∩C)=0.05

now, we can plug these values into formula

and we get

0.05=0.4*0.25

0.05=0.1

we can see that left side is not equal to right side

so, this is FALSE

(b)

We can use independent events formula

P(D∩A)=P(D)*P(A)

we are given

P(D)=0.25

P(A)=0.6

P(D∩A)=0.1

now, we can plug these values into formula

and we get

0.1=0.25*0.6

0.1=0.15

we can see that left side is not equal to right side

so, this is FALSE

(c)

We can use independent events formula

P(E∩A)=P(E)*P(A)

we are given

P(E)=0.5

P(A)=0.6

P(E∩A)=0.3

now, we can plug these values into formula

and we get

0.3=0.5*0.6

0.3=0.3

we can see that both sides are equal

so, this is TRUE

(d)

We can use independent events formula

P(D∩B)=P(D)*P(B)

we are given

P(D)=0.25

P(B)=0.4

P(D∩A)=0.15

now, we can plug these values into formula

and we get

0.15=0.25*0.4

0.15=0.1

we can see that left side is not equal to right side

so, this is FALSE


8 0
3 years ago
Is anyone can do this?
exis [7]

Answer:

Surface of35,875.86 cm^2

Voliume of 234,671.58 cm^3

Long and painful calculations

Ok, this is going to take some time. The volume is the sum of all the solids, minus the half cylinder that makes the "tunnel" beneath it. That said, we can split the item into 3 main shapes, and the cylinder: The pyramid in the top left, the square based prism below the pyramid, and the trapezoid prism to the right. I edited a bit the image with paint to add measurements. It's paint so quality is what it is and deal with comic sans as a font.

Let's find the total surface first. We have the surface of the four faces of the pyramid, which are triangles of base 54 and height (red line)\sqrt{36^2+(\frac{54}2)^2} =\sqrt{2025}=45cm, givins us a total area of 4\times \frac{bh}2 = 2\times 45\times 54 = 4860 cm^2

We add the two lateral faces of the left prism: they are two rectangles of side length 70 and 54, for a total area of 2(70)(54) = 7580 cm^2

Take the rectangle to the side of the prism, of sides 54 and 70-34 = 36, giving an area of 54\times 36 = 1944 cm^2

Pick the inclined "roof" of the right prism, again a rectangles, sides 54 and 61: surface is 3294 cm^2

Two side faces of the right building: first pick the height (magenta line), with pythagorean theorem again, equal to \sqrt{ 61^2-11^2} = \sqrt{3600} = 60 cm. The surface becomes 2 \frac{(B+b)h}2 = (34+45)(60)= 4740 cm^2

Missing the short sides and the half cylinder making the gallery. The sides - if you imagine un-hinging one and attaching to the bottom of the other - will make a rectangle of sides (45+70) cm and 54 cm with a circular hole in the middle. surface is (45+70)\times54 - \pi(54/2)^2 =3920.94 cm^2.

Finally, the half cylinder. It's a "rectangle) tall (60+54) cm - the length of the whole contraption, and long half the circle, or 27\pi. It's surface is  (60+54)\times\27\pi = 9664.92 cm^2

Done with surfaces. At this point we just add everything together. Grab a calculator and start adding up, if I didn't miss anything the total surface will be 35875.86 cm^2

Volumes now. You wished this was over? I totally did.

Bulk of the calculations are done luckly. It's just to cut and paste here and there.

Pyramid first. We know the side length, we know the height, volume is the usual formula

\frac 13l^2h = \frac 13 54^2\times 36= 33,048 cm^3

Cube beneath. This one is also easy Sides are 54cm, 54cm and 70cm, volume is their product:

54*54*70= 204,120 cm^3

Side prism now: again base surface times height, let's use the trapezoid as a base since we already have the area from above:

A_th = 2370\times54 = 127,980 cm^3

From this we take <u>half</u> a cylinder of radius 27 tall as the whole structure is long. \frac12 \pi r^2h = \frac12 \pi (27)^2(60+54) = 130,476.42 cm^3

We're done. Let's add the volume of the first 3 solids and subtract the last one - hope you have your calculator handy, to get in total a volume of 234,671.58 cm^3

Double and triple check numbers, even if I rand them with excel.

6 0
3 years ago
14k -14m - 23k + 59m
hoa [83]

-9k + 45m

you can reorganize the problem: 14k - 23k - 14m + 59m

from here, you can just do the somple math: -9k + 45m

May I have brainliest please? :)

5 0
3 years ago
Please Help!!!
lesya692 [45]

Answer:

  No, the clay will not pour out easily. I know this because the angle of the truck bed is less than 50°, which is the minimum angle for easy pouring.

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Sin = Opposite/Hypotenuse

If α represents the angle of the truck bed, this means ...

  sin(α) = 9/15

We can find α using the inverse sine function:

  α = arcsin(9/15) ≈ 36.87°

We note this angle is less than 50° so we expect the clay will not pour out easily.

7 0
3 years ago
3x-11=-1x-75<br> find the x value that would make this equation true
Tju [1.3M]

3x - 11 = -1x -75
3x = -1x -75 +11
3x + 1x = -75 + 11
4x = -64
x = -64/4
x = -16
7 0
4 years ago
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