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qwelly [4]
4 years ago
14

Ms. Dehejia has 25 sheets of colored paper. She wants to use the paper to create flyers announcing a recycling drive. She will u

se 1/4 sheet of paper for each flyer. How many flyers can Ms. Dehejia make? A. 4/25 flyer B. 6 1/4 flyers C. 10 flyers D. 100 flyers
Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
5 0

Answer:

  D.  100 flyers

Step-by-step explanation:

Since each flyer is 1/4 sheet of paper, one sheet of paper will make 4 flyers. Then 25 sheets of paper will make ...

  25 × (4 flyers) = 100 flyers

joja [24]4 years ago
4 0

Answer:

Option D is the correct answer.

Step-by-step explanation:

Ms. Dehejia has 25 sheets of colored paper

Number of papers Ms. Dehejia has = 25

She will use 1/4 sheet of paper for each flyer.

\texttt{Paper required to make each flyer = }\frac{1}{4}=0.25

We need to find how many flyers she can make with 25 sheets.

\texttt{Number of flyers = }\frac{\texttt{Number of sheets}}{\texttt{Paper required to make each flyer}}\\\\\texttt{Number of flyers = }\frac{25}{0.25}=100

Number of flyers can be made with 25 sheets = 100

Option D is the correct answer.

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balu736 [363]
The answer would be 0.4



You can first reduce this fraction:
40/100
=25
=
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2
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5
=0.4
=
0.4




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4 years ago
Celia Ltd. has invested in certain projects to avail future benefits for its company. Which project could be classified as an ex
ikadub [295]
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3 0
3 years ago
What is Divide −240 by 8
Yanka [14]

Answer: -30

Step-by-step explanation:

-240 / 8

= -30

4 0
3 years ago
Read 2 more answers
Given the following table and graph write the equation to represent the exponential function.
meriva

Answer:

The exponential equation is y = -2×(1/2)^x

Step-by-step explanation:

Ok we have a couple things to note here:

1) The horizontal asymptote of the function is the x axis (always nice)

2) At x=0, y=-2 (i.e, this function will be multiplied by -2 bc the exponent part will transform into one at x=0)

3) Then we need to ascertain the base of the exponential. Based on the facts that at x=1, y=-1 and the "a-value" is -2, we can set up an equation to find b:

y=a×b^x----> -1 = (-2)(b) ------> b=1/2

Therefore, the exponential equation is y = -2×(1/2)^x

Test:

At x = 0, y= -2

At x = -1, y = (-2)*(1/2)^-1 = (-2)*2 = -4

At x=2, y = (-2)*(1/2)^2= (-2)*(1/4) = -1/2

Thus we can be quite certain that this is correct

7 0
3 years ago
A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked
kogti [31]

A) The probability of picking a white tie 300 times = (\frac{1}{8}) ^{300}

B)  The probability of picking a blue tie 300 times = (\frac{1}{8}) ^{300}

C) The probability of picking a red tie 300 times = (\frac{1}{4}) ^{300}

D) the probability of picking a black tie 300 times = (\frac{3}{8}) ^{300}

E ) the probability of picking a maroon tie 300 times = (\frac{1}{8}) ^{300}

F) the probability of NOT picking a white tie 300 times = (\frac{7}{8}) ^{300}

Step-by-step explanation:

Here, the total number of black neckties  = 6

The total number of white neckties  = 2

The total number of red neckties  = 4

The total number of maroon neckties  = 2

The total number of blue neckties  = 2

The number of times the experiment is repeated = 300

A )  P(Picking a white tie)  = \frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}

= \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = (\frac{1}{8}) ^{300}

B) P(Picking a BLUE  tie)  = \frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = (\frac{1}{8}) ^{300}

C) P(Picking a Red  tie)  = \frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16}  = \frac{1}{4}

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = (\frac{1}{4}) ^{300}

D) P(Picking a Black  tie)  = \frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16}  = \frac{3}{8}

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = (\frac{3}{8}) ^{300}

E) P(Picking a maroon  tie)  = \frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16}  = \frac{1}{8}

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = (\frac{1}{8}) ^{300}

F) P(Picking a NOT whiten  tie)  = 1 - P( picking a white tie)

= 1-(\frac{1}{8} ) = \frac{8-1}{8}  = (\frac{7}{8} )

So, the probability of NOT  picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = (\frac{7}{8}) ^{300}

4 0
3 years ago
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