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Harrizon [31]
3 years ago
12

The graph of the parent function f(x) = x3 is transformed such that g(x) = f(–2x). How does the graph of g(x) compare to the gra

ph of f(x)
Mathematics
1 answer:
Gnoma [55]3 years ago
4 0
Every x value is multiplied by 3, expanding the graph
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Write an expression for the length of the rectangle.​ (Hint: Factor the area binomial and recall that Area=width times length)
cestrela7 [59]

Answer: A=l⋅w where A is the area of the rectangle, l is the length of the rectangle and w is the width of the rectangle.

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Determine whether Rolle's Theorem can be applied to f(x)=(x-1) (x-2)(x-3) on the closed interval [1,3]. Of Rolle's Theorem can b
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Step-by-step explanation:

6 0
3 years ago
during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

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By talking to the sales clerk at the hardware store, you find out that the burglar has two hideouts — the lake house and the cab
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Cabin is your answer
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Max earned a 85% on his test. if there were 40 questions on the test how many did he get correct?
wel
Max would have had to have gotten 34 out of 40 questions correct. Here's why:

\frac{x}{40} =  \frac{85}{100} &#10;&#10;(40)(85) = (x)(100)&#10;&#10;&#10;&#10;3400 = 100x&#10;&#10; \frac{3400}{100} = x&#10;&#10;&#10;34 =x&#10;
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