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2 years ago

I need answers asap... please

Mathematics

1 answer:

aleksandrvk [35]2 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

(4)

consider the left side

factor the numerator

cosx - cos³x = cosx(1 - cos²x)

$\frac{cosx(1-cos^2x)}{sinx}[/tex = [tex]\frac{cosxsin^2x}{sinx}$

cancel sinx on numerator/denominator

= cosxsinx =right side ⇒ verified

(5)

Consider the left side

expand the factors

(1 + cotΘ)² + (1 - cotΘ)²

= 1 + 2cotΘ + cot²Θ + 1 - 2cotΘ + cot²Θ

= 2 + 2cot²Θ

= 2(1 + cot²Θ) ← 1 + cot²Θ = cosec²Θ

= 2cosec²Θ = right side ⇒ verified

(6)

Consider the left side

the denominator simplifies to

cosxtanx = cosx × $\frac{sinx}{cosx}$ = sinx

$\frac{sin^2x(secx+cosecx)}{sinx}$

= sinx( $\frac{1}{cosx}$ + $\frac{1}{sinx}$ )

= $\frac{sinx}{cosx}$ + $\frac{sinx}{sinx}$

= tanx + 1 = right side ⇒ verified

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2 years ago

A die is rolled. What is the probability that the number is a factor of 6 or more than 2? Does this scenario represent mutually

goblinko [34]

Factors of 6 are : 1,2,3 and 6.

Let us find probability of getting the number that is a factor of 6.

$P(\text{ The number is a factor of 6})=\frac{4}{6} =\frac{2}{3}$

Now let us find probability of getting a number more than 2 (3,4,5,6).

$P(\text{ The number is a greater than 2})=\frac{4}{6} =\frac{2}{3}$

We can see that these two events are mutually inclusive events. We can find probability of mutually inclusive events by formula $P(\text{X or Y})=P(X)+P(Y)-P(\text{X and Y})$ .