Answer: 154.4 Fahrenheit
Step-by-step explanation: 68°C = ( 68× 9 / 5 + 32 ) = 154.4°F
The decimal approximation for the trigonometric function sin 28°48' is
Given the trigonometric function is sin 28°48'
The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.
To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°
sin (28°48') = sin(28° ₊ (48 × 1/60)°)
= sin(28° ₊ (48 /60)°)
= sin(28° ₊ 4°/5)
= sin(28° ₊ 0.8°)
= sin(28.8°)
= 0.481753
Therefore sin (28°48') is 0.481753.
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The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
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Answer:
20th: 100 nth: 5
Step-by-step explanation:
the table is multiplying by 5
so 5 × 20 = 100
