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galina1969 [7]
4 years ago
5

A street slopes upward at an angle of 15o with the horizontal. How high does it rise over a horizontal distance of 120 meters? E

xplain the thinking you use to arrive at your answer.

Mathematics
1 answer:
luda_lava [24]4 years ago
7 0

Answer: 32.15\ meters

Step-by-step explanation:

You can draw a right triangle (Observe the figure attached. It is not drawn to scale), where "x" is the the amount of meters the street rises over a horizontal distance of 120 meters.

You need to use the following Trigonometric Identity:

tan\alpha=\frac{opposite}{adjacent}

In this case, you can identify that:

\alpha=15\°\\\\opposite=x\\\\adjacent=120

Then, knowing these values, you can substitute them intotan\alpha=\frac{opposite}{adjacent}:

tan(15\°)=\frac{x}{120}

And finally, you must solve for "x" in order to find its value.

You get this result:

(tan(15\°)(120)=x\\\\x=32.15

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Answer:

1. f(x)=x^{2} and g(x)=-\sqrt{x}

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    Because the graph will have a hole at x=-1. This is, the graph is not defined for that particular x-value.

3.  f(x)=x^{2}+4

It has two complex roots, so there is no place in the graph where it crosses the x-axis.

Step-by-step explanation:

1. If we find the composite function f[g(x)] with the functions:

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g[f(x)]=-x

2.

Before finding the asymptotes, it's a good idea to factor both the numerator and denominator of the function, so we get:

f(x)=\frac{x^{2}+3x+2}{x^{2}+5x+4}

f(x)=\frac{(x+2)(x+1)}{(x+4)(x+1)}

we can now see that this function can be simplified. It is important to simplify this function so we don't confuse vertical asymptotes with holes in the graph, so when simplifying we get the following:

f(x)=\frac{x+2}{x+4}

now we can set the denominator equal to zero.

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The zeros of the function are located at the x-values that will turn the numerator of the simplified fraction equal to zero, so we get:

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Take a look at the graph of the function (See attached picture)

3.

This will happen when there are no real zeros. Take for example the function:

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In this case this problem has 2 non-real zeros:

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Step-by-step explanation:

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