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2 years ago

Only need answers to number 2 and 3 would be helpful ASAP

Mathematics

1 answer:

12345 [234]2 years ago

4 0

Answer:

2 is option 3

3 is option 2

Step-by-step explanation:

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9. What is the vertex of the function? f(x) = 3x² - 8x + 10

Delvig [45]

Answer:

The vertex of the function is (1.333, 4.667)

Step-by-step explanation:

1. Calculate -b / 2a. This is the x-coordinate of the vertex.

2. simply plug -b / 2a into the equation for x and solve for y.

$Y = 3x^{2} - 8x + 10\\Compare with the form of y = ax^{2} + bx + c\\So that means a = 3, b = -8, and c = 10.$

Calculate -b/2a:

$X = -(-8)/2(3)$

$X = 8/6$

This is equal to 1.33 recurring

Plug 8/6 for x and solve for y:

$Y = 3x^{2} - 8x + 10$

$Y = 3(\frac{8}{6})^{2} - 8(\frac{8}{6}) + 10$

$Y = \frac{48}{9} - \frac{64}{6} + 10\\$

This is equal to 4.66 reccuring.

7 0

1 year ago

3 Polnis

Minchanka [31]

Answer:

D.4.7%

Step-by-step explanation:

5 0

3 years ago

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.