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serious [3.7K]
3 years ago
7

Which triangle has hypotenuse Side B F? A cube. The top face has points G, B, C, F and the bottom face has points H, A, D, E. tr

iangle BFE triangle BFH triangle BFD triangle BFG
Mathematics
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

ΔBFG

Step-by-step explanation:

Since top face points are

  • G, B, C and F

and bottom face points are

  • H, A, D and E

The side BF can be a hypotenuse of the triangle BFG only

This triangle is on the top face and all the rest given triangles are formed by the points that are not on the same face, therefore BF can't be a hypotenuse of those, as ether B or F is becoming a right angle of the triangles.

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PLZ ANSWER APSP IM IN THE TEST RN!!!
olchik [2.2K]

Answer:

x = 38

y = 25

Step-by-step explanation:

To find x, you do

(2x + 5) = (3x - 33)

Subtract 2x from both sides to isolate x on one side, you get:

5 = (x - 33)

Add 33 to both sides to separate the normal number from the x, you get:

38 = x

From there, you plug x into one of the equations

2(38) + 5

The answer's 81, meaning that angle is 81 degrees. Using supplementary angles, you can find that angle ACD = 99, which you can use to find angle BCE. You'll get this equation:

(4y - 1) = 99

Add one to both sides to get rid of it, you get:

4y = 100

Divide by four, to get the y all alone:

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I hope this helped!

8 0
3 years ago
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A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
3 years ago
Nick divides 527 baseball cards evenly into 17 stacks. How many baseball cards are in each stack?
Anton [14]

Answer:

31..?

Step-by-step explanation:

517 divided by 27 equals 31

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3 years ago
The fire department reports that 2 out of every 25 fireworks are faulty.if a large fireworks show uses 500 fireworks, how many s
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Answer:

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Step-by-step explanation:

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