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Arada [10]
3 years ago
11

Need halp fast

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

Answer:

Step-by-step explanation:

13.

6 =x − 24

Collecting like terms

6 + 24 = x

x = 30

14.

10 +w/3 = 2

Multiply each term by 3

30 + w = 6

Collecting like terms

w = 6 - 30

w = -24

15.

13 = −11 − 4x

Collecting like terms

4x = -11 - 13

4x = -24

Dividing by 4

4x/4 = -24/4

x = -6

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A jug has 1 litre of 10% strength cordial. How much pure cordial needs to be added to make the strength 20%?
garik1379 [7]

Answer:

The volume or amount of pure cordial to be added to the solution to make the strength 20% is 125 ml

Step-by-step explanation:

The given parameters, are;

The volume of cordial in the jug = 1 litre

The percentage strength of the cordial = 10%

The proportion of the cordial that contains pure cordial = 0.1

Therefore, the volume of pure cordial in the jug = 0.1 × 1 = 0.1 × 1000 ml = 100 ml

The volume of the solvent = The volume of the solution -  The initial volume of pure cordial

∴ The volume of the solvent = 1000 ml - 100 ml = 900 ml

To increase the concentration of the cordial to 20% is given by the relation;

x/(x+900) = 0.2

Where;

x = The total volume of the pure cordial to be added to the pure solvent

Solving, gives;

x = 0.2×(x+900) = 0.2·x + 180

x -0.2·x = 180

0.8·x = 180

x = 180/0.8 = 225 ml

The total volume of the pure cordial to be added to the pure solvent = x = 225 ml

Therefore, the volume of pure cordial to be added to the initial volume of pure cordial in the solution, which is 100 ml, is therefore given as follows;

The volume or amount of pure cordial to be added = 225 ml - 100 ml = 125 ml.

The volume or amount of pure cordial to be added = 125 ml

8 0
2 years ago
Find the root of the equation 6x + 3= 0
mina [271]

The root of an equation f(x) is the x value(s) for which f(x) = 0.

So, if you have f(x) = 6x + 3, to find its root(s), you do 0 = 6x + 3, and then

0 - 3 = 6x + 3 - 3

-3 = 6x + 0

-3 = 6x

-3/6 = 6x/6

-1/2 = x

x = -1/2 is the one and only root (Linear functions will always have 0 or 1 root. They will have zero roots if they are horizontal lines of the form y = c, where c is any constant, and they will have one root if they are of the form y = mx + b, where m is not 0.)

5 0
3 years ago
Read 2 more answers
Find the values of x and y that make these triangles congruent by the HL Theorem.
RideAnS [48]

According to HL theorem if one leg and hypotenuse of one right triangle are equal to one leg and hypotenuse of other right triangle, then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

By using equation (1) next step is to plug in y+1 for x in equation (2). So,

2 ( y + 1) + 3 = 3y + 3

2y + 2 + 3 = 3y + 3 By using distribution property.

2y + 5 = 3y + 3

2y + 5 - 5 = 3y + 3 - 5 Subtract 5 from each side.

2y = 3y - 2

2y - 3y = -2 Subtract 3y from each sides.

-y = -2

So, y=2

Next step is to plug in y=2 in equation (1) to get the value of x. Hence,

x= 2+1

=3

So, x=3 and y=2 make these triangles congruent.

So, the correct choice is 3. x = 3, y = 2.

7 0
2 years ago
In the formula A(t) = A0ekt, A(t) is the amount of radioactive material remaining from an initial amount A0 at a given time t an
Alenkasestr [34]

Answer:  693 years

Step-by-step explanation:

Expression for rate law for first order kinetics is given by:

A(t) =A_0e^{kt}

k = rate constant

t = time taken for decomposition = 1

A_0 = Initial amount of the reactant

A_t = amount of the reactant left =A_0-\frac{0.1}{100}\times A_0=0.999A_0

0.999A_0=A_0e^{k\times 1}

0.999=e^k

k=-0.001year^{-1}

for half life : t=t_\frac{1}{2}

A_t=\frac{1}{2}A_o

Putting in the values , we get

\frac{1}{2}A_0=A_0e^{-0.001\times t_\frac{1}{2}

t_\frac{1}{2}=693 years

Thus half life of this isotope, to the nearest year is 693.

8 0
3 years ago
Help please I will give brainlyest 9th grade lidral arts
Assoli18 [71]

-5 + 12  is 7

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