Given:
Leela invests 500 at 4.5%
VI = 500 x 1.045^t
Adele invests 500 at 4.5% but 2 years before Leela invested
Vi = 500 x 1.045^2+t
<span>The total value of Adele’s account is approximately what percent of the total value of Leela’s account at any time, t?
</span>
[500 x 1.045^2+t / 500 x 1.045^t] * 100%
1.045² x 100% = 1.092 x 100% = 109.2%
To check: t =1
Adele: 500 x 1.045^2+1 = 500 x 1.045³ = 570.58
Leela: 500 x 1.045^1 = 500 x 1.045 = 522.50
570.58 / 522.50 = 1.092
1.092 x 100% = 109.20%
Answer:
Step-by-step explanation:
Putting value of x = 1/2 in the equation
8x - 3/x
8(1/2) - 3(1/2)
= 4 - 3/2
= 2.5 or 5/2
Answer:
Where are the drop down menus ?
Step-by-step explanation:
Answer:
The coordinates of N are (-3,-8)
Step-by-step explanation:
Here, we are going to use the internal division to find the coordinates of the point split the line segment MP in the ratio 3:4
Mathematically, that would be;
(x,y) = (nx1 + mx2)/(m + n), (ny1 + my2)/(m + n)
we have;
m = 3 and n = 4
M is (x1,y1) while N is (x2,y2)
we have;
(x,y) = (4(-12) + 3(9))/(3+4) , (4(-5) + 3(-12))/(3+4)
(x,y) = (-48 + 27)/7, (-20 -36)/7
(x,y) = (-21/7 , -56/7)
(x,y) = (-3,-8)
Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
