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Art [367]
3 years ago
15

You have a coupon for 10% off the sale price of a surfboard. which is the better buy? explain your reasoning. ● 40% off the regu

lar price ● 30% off the regular price and then 10% off the sale price
Mathematics
2 answers:
just olya [345]3 years ago
3 0
40 percent off because if there is 100 percent minus 40 that's 60 percent then if our work out the other one as 100 minus 30 equals 70. 70 the sale price divided by 10 because that's how much you get off equals 7. 30 plus 7 equals 37 which means you would only get 37 percent off.
N76 [4]3 years ago
3 0

Answer:

40% off the regular price

Step-by-step explanation:

The better buy is 40% off the regular price as you will have to pay 60% of the price of a surfboard. If instead of this, you get 30% off the regular price and then 10% off the sale price, the 30% off means that you would have to pay 70% of the price of the surfboard and then, they will calculate the 10% off using this price that is lower and at the end, your total discount would be 37% which means that you would have to pay 63% of the price which is higher.

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Can someone help me with this question
Alexxx [7]
Vas happening?
You break it down
3 ^5 is 3 x 3 x 3 x 3 x 3 = 729
4 ^ 5 is 4 x 4 x 4 x 4 x 4 = 1024
729 times 1024 = 746,496
12 ^ 10 is 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 x 12 = 6.19174e10
So the answer is incorrect
8 0
2 years ago
Read 2 more answers
Hannah claims that people who live in southern states spend 9 hours more per week outside than do people in northern states. She
vova2212 [387]

Answer:

b. Hannah is likely to be incorrect because 9 is not contained in the interval.

Step-by-step explanation:

Hello!

Hannah estimated per CI the difference between the average time that people spend outside in southern states and the average time people spend outside in northern states.

The CI is a method of estimation of population parameters that propose a range of possible values for them. The confidence level you use to construct the interval can be interpreted as, if you were to calculate 100 confidence interval, you'd expect that 99 of them will contain the true value of the parameter of interest.

In this example, the 99%CI resulted [0.4;8.0]hs

Meaning that with a 99% confidence level you'd expect the value of the difference between the average time people from southern states spend outside than the average time people from northern states spend outside is included in the interval [0.4;8.0]hs.

Now, she claims that people living in southern states spend 9 more hours outside than people living in northern states, symbolized μ₁ - μ₂ > 9

Keep in mind that if you were to test her claim, the resulting hypothesis test would be one-tailed

H₀: μ₁ - μ₂ ≤ 9

H₁: μ₁ - μ₂ > 9

And that the calculated Ci is tow-tailed, so it is not valid to use it to decide over the hypotheses pair. This said, considering that the calculated interval doesn't contain 9, it is most likely that Hannah's claim is incorrect.

I hope this helps!

6 0
2 years ago
A recently admitted class of graduate students at a large state university has a mean GRE verbal score of 650 with a standard de
hjlf

Answer:

The answer is below

Step-by-step explanation:

The z score is a score used to determine the number of standard deviations by which the raw score is above or below the mean, it is given by the equation:

z=\frac{x-\mu}{\sigma} \\\\\mu=mean, \sigma=standard\ deviation,x=raw\ score\\\\for\ a\ sample\ n:\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

Given that μ = 650, σ = 50. To find the probability that 5 students who have a mean of 490, we use:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{490-650}{50/\sqrt{5} } =-7.16

From the normal distribution table, P(x < 490) = P(Z < -7.16) = 0.0001 = 0.01%

Since only a small percentage of people score about 490, hence the local newspaper editor should write a scathing editorial about favoritism

4 0
3 years ago
19 x 50 =_fifties. Please help me
ivanzaharov [21]
Nine hundred and fifty
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2 years ago
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How much of a sample remains after three half-lives have occurred?
aleksklad [387]
12.5% of the sample. hope it helped :)
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3 years ago
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