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Ierofanga [76]
3 years ago
9

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, a

nd a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?
A)The graph of the function is positive on (–6, –2).
B)The graph of the function is negative on (negative infinity, 0).
C)The graph of the function is positive on (–2, 4).
D)The graph of the function is negative on (4, positive infinity).
Mathematics
2 answers:
Temka [501]3 years ago
3 1
The right answer for the question that is being asked and shown above is that: "B)The graph of the function is negative on (negative infinity, 0)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with<span>multiplicity 3.</span>
Norma-Jean [14]3 years ago
4 0

Answer:

-6,-2

Step-by-step explanation:

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Read 2 more answers
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