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Minchanka [31]
3 years ago
5

Last year, Josh had $20,000 to invest. He invested some of it in an account that paid 7% simple interest per year, and he invest

ed the rest in an account that paid 9% simple interest per year. After one year, he received a total of $1560 in interest. How much did he invest in each account?
Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer: $12000 was invested at 7% while $8000 was invested at 9%.

Step-by-step explanation:

Based on the information given in the question, let the amount that was invested at 7% be n.

Therefore,

0.07n + 0.09(20000 - n) = 1560

0.07n + 1800 - 0.09n = 1560

-0.02n = 1560 - 1800

-0.02n = -240

n = 240/0.02

n = 120

Therefore, $12000 was invested at 7% while $8000 was invested at 9%.

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Round the fraction to 0, 1/2, or 1.<br><br><br><br> 9/10
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Svetach [21]

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The second one (2) is a lie

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
PLEASE HELP IM STRUGGLING!!!​
Mnenie [13.5K]

Answer:

  • 10. 0.99
  • 11. -60
  • 12. 5.5

Step-by-step explanation:

<u>Use the slope formula:</u>

  • m = (y2 - y1)/(x2 - x1)

10.

  • m = (6.24 - 3.27)/(5 - 2) = 2.97/3 = 0.99

11.

  • m = (240 - 360)/(3 - 1) = -120/2 = -60

12.

  • m = (8.84 - 6.09)/(7 - 2) = 2.75/5 = 5.5
6 0
3 years ago
What is the y-intercept for the equation 4x+2y=6?
Romashka-Z-Leto [24]

Answer:

The y intercept is 3

(0,3)

Step-by-step explanation:

4x+2y=6

To find the y intercept, set x =0 and solve for y

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0+2y = 6

Divide by 2

2y/2 = 6/2

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The y intercept is 3

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6 0
2 years ago
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