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Feliz [49]
3 years ago
7

The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chancee choos

es x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions. She determines that x must be between 0 and 10 and y must be between 20 and 40. Determine if Chancee found the correct solution. If not, state the correct solution.

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

No, Chancee mixed up the variables, the correct solution is that x must be between 20 and 40 and y must be between 0 and 10.

Step-by-step explanation:

Here, x and y are positive integers,

Such that, their sum is not more than 40,  

i.e. x + y ≤ 40 where x, y ≥ 0,

⇒ y ≤ 40 - x                 ...............(1),

Their difference is at least 20,

i.e. x - y ≥ 20

-y ≥ 20 - x

⇒ y ≤ x - 20   ............(2),

Graphing y ≤ 40 - x :

Related equation of inequality (1),

y = 40 - x

if x = 0, y = 40,

if y = 0, 0 = 40 - x ⇒ x = 40,

'≤' represents a solid line,

Join the points (0, 40) and (40, 0) by solid line.

Graphing y ≤ x - 20:

Related equation of inequality (1),

y = x - 20,

if x = 0, y = -20,

if y = 0, 0 = x - 20 ⇒ x = 20,

'≤' represents a solid line,

Join the points (0, -20) and (20, 0) by solid line.

By graphing we obtained a feasible region that is the solution of the system of inequalities (1) and (2) ( shown below ),

In which,

20 ≤ x ≤ 40 and 0 ≤ y ≤ 30

Hence, Chancee did not find the correct solution.

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Flura [38]
30/12 in simplest form is 5/2 (cause 6 * 5 = 30 and 6 * 2 = 12)
40/16 in simplest form is 5/2 (cause 8 * 2 = 16 and 8 * 5 =40)
so yes they're equivalent;
30/12 = 40/16
Hope that helps :D have a nice day!
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A)

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