So you are seeing how much time it'll take so you solve for "t", the time. <span>So you take the formula A=Pe^(rt) </span> <span>A=2000 because it's the end value </span> <span>P=20 because it's the starting value </span> <span>r=.85 since 85%=.85 and .85 is the rate </span> <span>Plug the values in and you get 2000=20e^(.85t) </span> <span>What you do is you divide by 20 so you get 100=e^(.85t) </span> <span>Take the natural logarithm of both sides 'cause of e and a natural log is written as ln so you get </span> <span>ln 100=.85t ln e and because you can use the power rule you end up with .85t ln e and </span> <span>ln e=1 so you have ln 100 = .85t so you divide by .85 so (ln 100)/.85=t and t=5.4178472776331 </span> <span>hours </span> <span>3. Exponential decay: </span> <span>A= Pe^(rt) </span> <span>where </span> <span>A is the final amount </span> <span>P is the initial value </span> <span>r is rate of decay </span> <span>t is time (years) </span> <span>Let's say x is the initial amount then (1/2)x=xe^(32r) </span> <span>I used x because the value isn't given but anyway division by x would give you 1/2=e^(32r) </span> <span>Take the ln of both sides so ln 1/2=32r ln e and then ln e=1 so ln 1/2=32r. </span> <span>Divide both sides by 32 and you'd get (ln 1/2)/32=r and r= -0.021660849392498 </span> <span>4. Another depreciation question. </span> <span>Each year the item retains 88% of its last-year value. </span> <span>Solve: 250,000(0.88)^x = 100,000 </span> <span>0.88^x = 0.4 </span> <span>x = [log0.4]/[log0.88] </span> <span>x = 7.168 years </span>