Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Step-by-step explanation:
<u>Given coordinates of the rectangle ABCD:</u>
- A(0, 0), B(a, 0), C(x, y), D(0, b)
Lets first find coordinates of C
We can see that A and B are on same line horizontally, so C and D will be on the parallel line
The distance AB and CD are equal also distance AD and BC are equal, therefore
- AB = a - 0 = a, CD = a
- AD = b - 0 = b, BC = b
<u>So the coordinates of C are:</u>
<u>Now the diagonals:</u>
- AC = √(a-0)² + (b-0)² = √a²+b²
- BD =√(0-a)² + (b -0)² = √a² + b²
Since AC = BD, we can state they are congruent