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2 years ago

A shopkeeper marks the price of an article

Mathematics

1 answer:

marin [14]2 years ago

3 0

Answer:

The gain percent made by shopkeeper is 10.5%.

Step-by-step explanation:

Given:

Price at which goods are marked = 30%

Discount on the marked price = 15%

To Find:

Gain percentage of the shopkeeper

Solution:

Let the cost price of the product be = 100

Therefore,

MP = 30 + 100 = 130

Since discount is 15%. thus -

Discount = 15/100 x 130

= 19.5

Selling price = MP - Discount

SP = 130 - 19.5

= 110.5

Profit = SP - CP

= 110.5 - 100

= 10.5

Calculating the gain%

Gain% = 10.5/100 x 100

= 10.5

Answer: The gain percent made by shopkeeper is 10.5%.

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padilas [110]

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1 year ago

A water tank is currently three-quarters full. If 2500 gallons are drained, the tank will be one-third full. How many gallons of

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2 years ago

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kondaur [170]

<u>Answer: </u>

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

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Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

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Eva8 [605]

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