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Andrej [43]
3 years ago
11

A shopkeeper marks the price of an article

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

The gain percent made by shopkeeper is 10.5%.

Step-by-step explanation:

Given:

Price at which goods are marked = 30%

Discount on the marked price = 15%

To Find:

Gain percentage of the shopkeeper

Solution:

Let the cost price of the product be = 100

Therefore,

MP = 30 + 100 = 130

Since discount is 15%. thus -

Discount = 15/100 x 130

= 19.5

Selling price = MP - Discount

SP = 130 - 19.5

= 110.5

Profit = SP - CP

= 110.5 - 100

= 10.5

Calculating the gain%

Gain% = 10.5/100 x 100

= 10.5

Answer: The gain percent made by shopkeeper is 10.5%.

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Step 2: Flip the equation.

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Step 3: Add 30 to both sides.

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1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.

2)The solution for b² - 4b + 4 = 0 is x=2.

<u>Step-by-step explanation</u>:

The general form of quadratic equation is ax²+bx+c = 0

where

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<u>To find the roots :</u>

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1) The given quadratic equation is m² - 5m - 14 = 0.

From the above equation, it can be determined that b = -5 and c = -14

The roots are -7 and 2.

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The solution is given by (x-7) (x+2) = 0.

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From the above equation, it can be determined that b = -4 and c = 4

The roots are -2 and -2.

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The solution is given by (x-2) (x-2) = 0.

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Now, if the inlet can fill it in 7 hours, that means that it is adding 10 gallons per hour. (70 gal/7 hours = 10 gal/hr)

For the outlet, use the same process, and you find that it drains the vat at 7 gallons per hour. 

So, if you subtract the outlet from the inlet, you get 10 - 7 = 3 gallons per hour added. 

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