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3 years ago

7

In the diagram, the length of segment QV is 15 units.

2 answers:

Andrews [41]3 years ago

6 0

Answer:

The answer is 15 units.

Step-by-step explanation:

The reason it is 15 units is because We know that QV = 15 and TQ = TS, QV = SV;4 x - 1 = 154 x = 15 + 14 x = 16x = 16 : 4 = 4 henceforth the answer being 15 units

EastWind [94]3 years ago

6 0

Answer:

15

Step-by-step explanation:

Since the length of the segment is the same it would be parallel which would be 15=15

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15 is 30% of what number?

dangina [55]

#1---> let the number you are trying to find be x for the following questions

30%*x=15
x=15/30%
x=50

#2
10%*x=14
x=14/10%
x=140

#3
(4/32)*100
is the same as (1/8)*100= 12.5%

#4
1%* x=11
x=11/1%
x=1100

by the way * means multiply

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3 years ago

Each morning, a cafe sells at most 20 freshly squeezed orange juices. Write an inequality that represents this situation. Let x

OverLord2011 [107]

Answer:

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Step-by-step explanation:

3 0

3 years ago

Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: <em>"the cost of working for 100 hours is $130000"</em>

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

<u>(a) Functions c(n) and n(h)</u>

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

<u>(b) Function c(n(h))</u>

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

<u>(c) Find c(n(100))</u>

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

<u>(d) Interpret (c)</u>

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

A blue line with 5 orange tick marks then one red tick mark then 4 orange tick marks. the number zero is above the red tick mark

MrRa [10]

The final displacement is 2cm in the right.

Given that the object begins from 0 and moves 3 cm towards the left side and then, 5 cm towards the right side.

The displacement is known as shortest distance between the initial and final positions.

Let the x-axis be the positive, +ve, and on the right side and negative -ve on the left side.

Thus, displacement would be:

D= 0 -3 +5

D= 2 cm

This implies that the object displaces 2cm towards the right side

Hence, the final displacement when object moves from 0 and 3 cm to the left and then 5 cm to the right is 2cm in the right side.

Learn about Displacement from here brainly.com/question/24212575

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4 0

2 years ago

What is 100x200? give answer and explain how?

Scrat [10]

100×200=20000
________________

7 0

3 years ago

Read 2 more answers