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Verdich [7]
3 years ago
12

A)If three students scored 70 on a test and three other students scored 89 on the same test, find the mean, median & mode fo

r the test scores.
b) the mean scourge on a set of 21 tests is 74. What’s the sum of all the test scores?
Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

a. Mean = 84.25. Median = 89. Mode = 89. b. Sum = 1554.

Step-by-step explanation:

a. Mean: add together 70, 89, 89, and 89, to get 337. Divide by 4 to get the mean, which is 84.25.

Median: The "middle" number, which is 89.

Mode: The number that occurs most often, which is 89.

b. 21 times 74 equals 1554. This is the sum of the test scores.

Hope this helps!

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Answer: 204 students

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12 students can fit at 1 table and there are 17 tables.

So we have (12)(17) which is 204.

So the greatest number of students that can be seated din the cafeteria is 204 students.

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Answer:

It is so easy u should get this right.

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Solve the equation in the complex number system. x^2-12x+40=0
mylen [45]

solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Step-by-step explanation:

Solve the equation:

x^2-12x+40=0

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x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i

So, solving the equation x^2-12x+40=0 we get x=6+2i\,\,and\,\,x=6-2i

Keywords: Solving quadratic equation

Learn more about Solving quadratic equation at:

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