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2 years ago

Triangle IJK is similar to triangle LMN. Find the measure of side LM. Round your answer to the nearest tenth if necessary.

Mathematics

1 answer:

Andre45 [30]2 years ago

8 0

Answer:

It's either 39.2 or 39.3 (a more accurate answer) because it depends on what you round by. since it's Delta Math, you should get 2 attempts.

Step-by-step explanation:

Since they are similar, they are proportional.

54/11=4.90909091 or 4.9

Multiply 11 by 4.90909091 and you get 54

Multiply 8 by 4.90909091 and you get 39.3

if you multiply by 4.9 you get 39.2

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How many odd positive integers less than 300 can be written using the numbers 2,4,5,and 8

DENIUS [597]

Answer:

Step-by-step explanation:

Given four numbers 2, 4, 6, 8.

The numbers can be arranged to form an odd number which is less than 300.

That means we have three spaces to fill this. We can try out the different combination of the numbers.

Note that the numbers should be odd. So, in the unit digit should only be 5. 2, 4, 8 would make the number even.

Also, the first digit can only be two because other numbers would make it bigger than 300.

So, 2 ___ 5 is fixed. The middle digit could be any of the four.

So, 225; 245; 255 and 285 all satisfy the conditions.

So, four numbers can be formed.

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3 years ago

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3 years ago

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3 years ago

Write the formula for the area of a triangle, A=1/2bh in terms of h. Find the height of a triangle when A = 18 in. squared and b

Elena L [17]

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3 years ago

Given points A(-1, -2) and B(2, 4) where AP: BP=1:2, find the locus of point P.

koban [17]

Answer:

$x^2 + 4x + y^2 +8y = 0$

Step-by-step explanation:

Given

$A = (-1,-2)$

$B = (2,4)$

$AP:BP = 1 : 2$

Required

The locus of P

$AP:BP = 1 : 2$

Express as fraction

$\frac{AP}{BP} = \frac{1}{2}$

Cross multiply

$2AP = BP$

Calculate AP and BP using the following distance formula:

$d = \sqrt{(x - x_1)^2 + (y - y_1)^2}$

So, we have:

$2 * \sqrt{(x - -1)^2 + (y - -2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

$2 * \sqrt{(x +1)^2 + (y +2)^2} = \sqrt{(x - 2)^2 + (y - 4)^2}$

Take square of both sides

$4 * [(x +1)^2 + (y +2)^2] = (x - 2)^2 + (y - 4)^2$

Evaluate all squares

$4 * [x^2 + 2x + 1 + y^2 +4y + 4] = x^2 - 4x + 4 + y^2 - 8y + 16$

Collect and evaluate like terms

$4 * [x^2 + 2x + y^2 +4y + 5] = x^2 - 4x + y^2 - 8y + 20$

Open brackets

$4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20$

Collect like terms

$4x^2 - x^2 + 8x + 4x + 4y^2 -y^2 +16y + 8y + 20 - 20 = 0$

$3x^2 + 12x + 3y^2 +24y = 0$

Divide through by 3

$x^2 + 4x + y^2 +8y = 0$

3 0

3 years ago