Answer:
22 peaches
Step-by-step explanation:
I hope this help! :)
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Out of the four options,
A. 99 cm B. 105.98 cm C. 90 cm D. 104.5 cm,
option A is the correct answer.
Because 1 m = 100 cm and this is the nearest approximation. Thus, the<span>A student used A tape measures to estimate the length of a meterstick manufactured to he exactly 1 meter. </span>
Take the answer you get from that and add it to 270. That is your answer.
37
Line up the data, separate into quarters
Take the highest number in the 3rd quarter from the lowest in the 2nd