Answer:
soln,
write the question
=9x^2+1-6x-2×9x^2+25+9x^2+25
=9x^2+1-6x-18x^2+25+9x^2+25
=9x^2-18x^2+9x^2+1+25+25-6x
=51-6x
if(3x+1)^2 mean that (3x+1)has power of 2 and u don't have to use the formula this is the answer
Step-by-step explanation:
it's just BODMAS method
Answer:
Step-by-step explanation:
The total number of lines, n(U) = 18
Let the number of lins with verb be n(V) = 11
Let the number of lines with adjectives be n(A) = 13
n(V n A) = 8
Find the number of lines that have a verb but no adjective, that is, n(V n A')
Mathematically, according to sets theory,
n(V) = n(V n A) + n(V n A')
So,
n(V n A') = n(V) - n(V n A) = 11 - 8 = 3.
Hence, only 3 lines have a verb but no adjectives.
Answer:
f = 2
g = 8
h = -9
k = 40
m = 1
Step-by-step explanation:
Equation 1:
23f - 17 = 29
Add 17 to both sides. This undoes the -17.
23f = 29 + 17
Add 17 to 29 to get 46.
23f = 46
Divide both sides by 23. This undoes the multiplication by 23.
f = 46/23
Divide 46 by 23 to get 2.
f = 2
Equation 2:
2(3g + 4) = 56
Divide both sides by 2. This undoes the multiplication by 2.
3g + 4 = 56/2
Divide 56 by 2 to get 28.
3g + 4 = 28
Subtract 4 from both sides. This undoes the +4.
3g = 28 - 4
Subtract 4 from 28 to get 24.
3g = 24
Divide both sides by 3. This undoes the multiplication by 3.
g = 24/3
Divide 24 by 3 to get 8.
g = 8
Equation 3:
h + 9 = 0
Subtract 9 from both sides. This undoes the +9.
h = 0 - 9
Any number subtracted from 0 gives its negation.
h = -9
Equation 4
3(k - 8) = 96
Divide both sides by 3. This undoes the multiplication by 3.
k - 8 = 96/3
Divide 96 by 3 to get 32.
k - 8 = 32
Add 8 to both sides. This undoes the -8.
k = 32 + 8
Add 8 to 32 to get 40.
k = 40
Equation 5:
5m - 5 = 0
Add 5 to both sides. This undoes the -5
5m = 0 + 5
Anything plus 0 gives itself.
5m = 5
Divide both sides by 5. This undoes the multiplication by 5
m = 5/5
Anything divided by itself gives you 1.
m = 1
The anser is all of the above please make brainlyleist
