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2 years ago

What is the estimate for 243?

Mathematics

1 answer:

Tatiana [17]2 years ago

4 0

Answer:

200

Step-by-step explanation:

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Evaluate F(3)for the piecewise function which value represents F(3)

Lynna [10]

Answer:

When x = 3, use -3x -2

-3(3) - 2 = -9 - 2 = - 11

6 0

2 years ago

Susan Marciano invested part of her 19000 bonus in a fund that paid an 11% profit and invested the rest in stock that suffered a

ioda

The amount invested at 11% is $5,000

The amount invested in stock is $14,000

What is the net profit on both investments?

The profit of each investment is the rate of return or loss multiplied by the amount invested

Let us assume that x was invested at 11% and the remaining 19000-x was invested at a loss rate of 3%

net profit=(11%*x)+(19000-x)*-3%

net profit=130

130=(11%*x)+(19000-x)*-3%

130=0.11x-570+0.03x

130=0.14x-570

130+570=0.14x

700=0.14x

x=700/0.14

x=$5,000

Amount invested in stock=19000-x

Amount invested in stocks=19000-5000

Amount invested in stocks=$14,000

Find out more about combined investments on:brainly.com/question/2166053

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8 0

6 months ago

If f is a scalar field and F, G are vector fields, then f F, F · G, and F × G are defined by the following. (f F)(x, y, z) = f(x

valentina_108 [34]

Answer:

Step-by-step explanation:

Consider curl $(fF)$ where $f$ is a scalar function and F is a vector function

$F=F_{1}i +F_{2}j +F_{3}k$

i j k

$curl(fF) = \frac{\partial}{\partial x}$ $\frac{\partial}{\partial y}$ $\frac{\partial}{\partial z}$

$fF_{1}$ $fF_{2}$ $fF_{3}$

$curl(fF)=i(\frac{\partial}{\partial y}(fF_{3})-\frac{\partial}{\partial z}(fF_{2}))-j(\frac{\partial}{\partial x}(fF_{3})-\frac{\partial}{\partial z}(fF_{1}))+k(\frac{\partial}{\partial x}(fF_{2})-\frac{\partial}{\partial y}(fF_{1}))$

$=i(\frac{\partial}{\partial y}(F_{3})+\frac{\partial}{\partial y}(f)-\frac{\partial}{\partial z}(F_{2})-\frac{\partial}{\partial z}(f))-j(\frac{\partial}{\partial x}(F_{3})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial z}(F_{1})-\frac{\partial}{\partial z}(f))+k(\frac{\partial}{\partial x}(F_{2})+\frac{\partial}{\partial x}(f)-\frac{\partial}{\partial y}(F_{1})-\frac{\partial}{\partial y}(f))$