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Hoochie [10]
4 years ago
11

Could someone help????

Mathematics
2 answers:
kap26 [50]4 years ago
7 0
Yes, so 3 1/2 + 3 1/2= 7 here you go buddy!
LUCKY_DIMON [66]4 years ago
3 0

Answer:

3 1/2 + 3 1/2 is 7

Step-by-step explanation:

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I have no clue what to do
igor_vitrenko [27]

Answer:

4x + 3y = 12

Step-by-step explanation:

6 0
2 years ago
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Solve. please and thank you
Cerrena [4.2K]
D I’m I think I’m pretty sure hope it helps
8 0
3 years ago
What is the range of the function y = RootIndex 3 StartRoot x + 8 EndRoot?
AlladinOne [14]

Answer:

- ∞ < y < ∞

Step-by-step explanation:

The given function is, y = \sqrt[3]{x + 8}.

Now, the origin function of this above function is, y = \sqrt[3]{x} which has real y-values as output for all real x-values input.

Hence, the function y = \sqrt[3]{x + 8} will ba valid for all real values of x and will have real y-value corresponding to each x-value.

Therefore, the range of this function i.e. the y-value of this function will be  

- ∞ < y < ∞. (Answer)

7 0
4 years ago
Read 2 more answers
A.) Prove that the ratio of two rational numbers must be rational.
Luda [366]

Answer:

v — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc

Step-by-step explanation:

c — Prove that (ax + b)/(cx + d) is irrational if and only if ad = bc. ... If b = 0, we have (ax + b)/(cx + d) = 0 is rational; if c = 0, since ... nonzero integers m, n ∈ Z. Then we have ... Proof. We prove by induction. When n = 1, both sides are 1/2 hence the ... So there are less than (k + 1)(2k + 1)k+1 (actually muc

4 0
3 years ago
Jorge asked each of the 24 students in his class if they play a musical instrument. He also asked each
HACTEHA [7]

Answer:

Here's what I get.  

Step-by-step explanation:

I have highlighted the given information in the table below.

Here's how I got the other numbers

1. Students who don't  play a sport

Total students                               = 24

Students who play a sport           = <u> 14 </u>

Students who don't  play a sport = 10

2. Students who play a sport but not music

Play a sport                      = 14

Play a sport and music    = <u> 6 </u>

Play sport but not music =   8

3. Students who play music but not a sport

Don't play a sport                  = 10

Play neither music nor sport =<u>  3 </u>

Play music but not sport        = 7

4. Total who play music

Play both music and sport   =  6

Play music but not sport      =<u>   7</u>

Total who don't  play music = 13

5. Total who don't play music

Play a sport but not music    = 8

Play neither sport nor music =<u> 3</u>

Total who don't  play music  = 11

 

4 0
3 years ago
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