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Rasek [7]
4 years ago
5

Find the dy/dx xy=(x+y)^4

Mathematics
1 answer:
JulijaS [17]4 years ago
8 0

Answer:

dy/dx =   (4 (x + y)^3 - y) / ( x - 4(x + y)^3).

Step-by-step explanation:

xy = (x + y)^4

Using implicit differentiation:

x dy/dx + y*1  = 4 (x + y)^3 * (1 + dy/dx)

x dy/dx + y =  4 (x + y)^3 + 4 dy/dx (x + y)^3

x dy/dx -  4 dy/dx (x + y)^3 =  4 (x + y)^3 - y

dy/dx( x - 4(x + y)^3) =  4 (x + y)^3 - y

dy/dx =   (4 (x + y)^3 - y) / ( x - 4(x + y)^3)

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