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worty [1.4K]
3 years ago
11

What is 1/4x+5=4 ??

Mathematics
2 answers:
iVinArrow [24]3 years ago
4 0

Answer:

Depends on what you mean by 1/4x (see below)

Step-by-step explanation:

For 1/4(x)

1/4x+5 = 4 -> subtract 5 from both sides

1/4x = -1 -> multiply both sides by 4

x = -4

OR

For 1/(4x)

1/4x+5 = 4 -> subtract 5 from both sides

1/4x = -1 -> cross multiply (-1 = -1/1)

-4x = 1 -> divide both sides by -4

x = -1/4

velikii [3]3 years ago
3 0
Here is the solution for your equation-

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navik [9.2K]

Answer:

(-10,3),(9,0)

Step-by-step explanation:

5 0
3 years ago
The sum of 3 consecutive even integers is 18<br>​
larisa [96]

Answer:

4,6,8

Step-by-step explanation:

Let x = 1st even integer

x+2 =2nd even integer

x+4 =3nd even integer

x+ x+2 + x+4 = 18

Combine like terms

3x+6 = 18

Subtract 6 from each side

3x+6-6=18-6

3x= 12

Divide by 3

3x/3 =12/3

x = 4

x+2 = 6

x+4 = 8

5 0
2 years ago
Plz explain it to me? and answer
Viefleur [7K]
The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.

We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.

Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.

Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet

To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.

19.5 feet + 19.5 feet = 39 feet

Therefore, the area of Noshi's desk is 39 feet.

Hope this helps! :)
7 0
3 years ago
What is the fractional form of 0.8
Sholpan [36]

Answer:

4/5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I’ve never been so confused, this is due in a few minutes, pls help if you can!
algol13

Given:

m(ar QT) = 220

m∠P = 54

To find:

The measure of arc RS.

Solution:

PQ and PT are secants intersect outside a circle.

<em>If two secants intersects outside a circle, then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.</em>

$\Rightarrow \angle P = \frac{1}{2} (m \ ar (QT) - m \ ar (RS ))

$\Rightarrow 54 = \frac{1}{2} (220- m \ ar (RS ))

Multiply by 2 on both sides.

$\Rightarrow 2 \times 54 = 2 \times  \frac{1}{2} (220- m \ ar (RS ))

$\Rightarrow 108= 220- m \ ar (RS )

Subtract 220 from both sides.

$\Rightarrow 108-220= 220- m \ ar (RS )-220

$\Rightarrow -112= -m \ ar (RS )

Multiply by (-1) on both sides.

$\Rightarrow (-112)\times(-1)= -m \ ar (RS )\times(-1)

$\Rightarrow 112= m \ ar (RS )

The measure of arc RS is 112.

6 0
3 years ago
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