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3 years ago

What is 1/4x+5=4 ??

Mathematics

2 answers:

iVinArrow [24]3 years ago

4 0

Answer:

Depends on what you mean by 1/4x (see below)

Step-by-step explanation:

For 1/4(x)

1/4x+5 = 4 -> subtract 5 from both sides

1/4x = -1 -> multiply both sides by 4

x = -4

For 1/(4x)

1/4x+5 = 4 -> subtract 5 from both sides

1/4x = -1 -> cross multiply (-1 = -1/1)

-4x = 1 -> divide both sides by -4

x = -1/4

velikii [3]3 years ago

3 0

Here is the solution for your equation-

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Solve this linear equation for p.

Fynjy0 [20]

Answer:

11.2

Step-by-step explanation:

divide 160 by 14.3

6 0

3 years ago

Read 2 more answers

Can someone show me how to factor this? 5k-35

kaheart [24]

Sure.
Can you find a number that goes into both terms, 5k and 35 ?
How about 5 ?

(5k - 35) = 5 times (k - 7) .

6 0

3 years ago

Read 2 more answers

Question 1 of 10

Archy [21]

Answer:

A. y = 7(x + 1)²-3

Step-by-step explanation:

Parabola:

$y = 7x^{2} + 14x + 4$

$y = 7(x^{2} + 2x) + 4$

Putting into vertex form, remember that:

$(x + a)^{2} = x^{2} + 2ax + a^{2}$

In this question:

$x^{2} + 2x$ , to put into this format:

$x^{2} + 2x + 1 = (x + 1)^{2}$

We add one inside the parenthesis to do this. The parenthesis is multiplied by 7, so for the equivalent, we also have to subtract 7. Then

Vertex form:

$y = 7(x^{2} + 2x + 1) + 4 - 7$

$y = 7(x + 1)^{2} - 3$

So the correct answer is:

A. y = 7(x + 1)²-3

3 0

3 years ago

Please help w this! Its a calculus question! look at the picture for the problem,

neonofarm [45]

Since you mentioned calculus, perhaps you're supposed to find the area by integration.

The square is circumscribed by a circle of radius 6, so its diagonal (equal to the diameter) has length 12. The lengths of a square's side and its diagonal occur in a ratio of 1 to sqrt(2), so the square has side length 6sqrt(2). This means its sides occur on the lines $x=\pm3\sqrt2$ and $y=\pm3\sqrt2$ .

Let $R$ be the region bounded by the line $x=3\sqrt2$ and the circle $x^2+y^2=36$ (the rightmost blue region). The right side of the circle can be expressed in terms of $x$ as a function of $y$ :

$x^2+y^2=36\implies x=\sqrt{36-y^2}$

Then the area of this circular segment is

$\displaystyle\iint_R\mathrm dA=\int_{-3\sqrt2}^{3\sqrt2}\int_{3\sqrt2}^{\sqrt{36-y^2}}\,\mathrm dx\,\mathrm dy$

$=\displaystyle\int_{-3\sqrt2}^{3\sqrt2}(\sqrt{36-y^2}-3\sqrt2)\,\mathrm dy$

Substitute $y=6\sin t$ , so that $\mathrm dy=6\cos t\,\mathrm dt$

$=\displaystyle\int_{-\pi/4}^{\pi/4}6\cos t(\sqrt{36-(6\sin t)^2}-3\sqrt2)\,\mathrm dt$

$=\displaystyle\int_{-\pi/4}^{\pi/4}(36\cos^2t-18\sqrt2\cos t)\,\mathrm dt=9\pi-18$

Then the area of the entire blue region is 4 times this, a total of $\boxed{36\pi-72}$ .

Alternatively, you can compute the area of $R$ in polar coordinates. The line $x=3\sqrt2$ becomes $r=3\sqrt2\sec\theta$ , while the circle is given by $r=6$ . The two curves intersect at $\theta=\pm\dfrac\pi4$ , so that

$\displaystyle\iint_R\mathrm dA=\int_{-\pi/4}^{\pi/4}\int_{3\sqrt2\sec\theta}^6r\,\mathrm dr\,\mathrm d\theta$

$=\displaystyle\frac12\int_{-\pi/4}^{\pi/4}(36-18\sec^2\theta)\,\mathrm d\theta=9\pi-18$

so again the total area would be $36\pi-72$ .

Or you can omit using calculus altogether and rely on some basic geometric facts. The region $R$ is a circular segment subtended by a central angle of $\dfrac\pi2$ radians. Then its area is