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djverab [1.8K]
2 years ago
13

A theater can seat 170 people. The number of rows is 7 less than the number of seats in each row. How many rows of seats are the

re?
Mathematics
1 answer:
maks197457 [2]2 years ago
5 0
Answer:number of rows =10
number of places in row = 17

Step-by-step explanation:
number of rows =N
number of places in row = N+7
N(N+7)=170
N^2+7n-170=0
(N+17)(N-10)=0
N1=-17
N2=10
We can`t take negative value for quantity of smth so we throw N1 away
From that number of rows =10
number of places in row = 10+7=17
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MariettaO [177]
W - 2.76 = 6.7

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W - 2.76 (+2.76) = 6.7 (+2.76)

W = 6.7 + 2.76

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Mary​'s car will go 261 miles on 14.5 gallons of gasoline in highway driving.
suter [353]

Answer:

a) 91 1/6 gallons

b) 2502 miles

Step-by-step explanation:

You are given a number of miles and a number of gallons for the car. The ratio of these numbers is ...

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We presume this value is constant for this car. Then the questions can be answered by forming and solving a proportion:

a) 1641 miles/(gallons) = 18 mi/(1 gal)

Multiplying by gallons and dividing by 18 mi/gal, we get

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It will take 91 1/6 gallons of gasoline for Mary to drive to her friend's house.

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b) Same deal, but the miles are unknown.

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Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose
Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

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Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

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x is the number of sucesses

&#10;e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson mean:

\mu = 0.2

a. What is the probability that a disk has exactly one missing pulse?

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This is P(X = 1).

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

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P(X \geq 2) = 1 - P(X < 2)

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c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

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P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671

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