Ask question

Ask question

All categories

2 years ago

9

What is the result of a division problem

2 answers:

Sonbull [250]2 years ago

6 0

Quotient. A/B=C C is the quotient.

Vikentia [17]2 years ago

4 0

The result or answer of a division problem is called a quotient

You might be interested in

One sample of n = 10 scores has a mean of M = 8, and a second sample of n = 5 scores has a mean of M = 2. If the two samples are

schepotkina [342]

Answer:

The mean for the combined sample = 6.

Step-by-step explanation:

We have been given that one sample of n = 10 scores has a mean of M = 8.

So the sum of 10 scores for 1st sample will be: $10\times 8=80$

We are also told that second sample of n = 5 scores has a mean of M = 2.

So the sum of 5 scores for 2nd sample will be: $5\times 2=10$

When the both samples are combined, so total points will be: $80+10=90$ and total scores will be $10+5=15$ .

$\text {Mean for the combined sample}=\frac{\text{Total points of both data sets}}{\text{Total scores of both data sets}}$

$\text {Mean for the combined sample}=\frac{90}{15}$

$\text {Mean for the combined sample}=6$

Therefore, the mean for the combined sample will be 6.

6 0

2 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

Which one of these is not a step used when constructing an inscribed equilateral triangle using technology?

dusya [7]

The third one duhhh, Ik this stuff

6 0

2 years ago

What is the product?

LenaWriter [7]

Answer:

$21x^{7}y^{11}$

Step-by-step explanation:

Remove the parentheses and take out the constansts.

$(7 x 3) x^{2} x^{5} y^{3} y^{8}$

Simplify 7 x 3 to 21.

$21x^{2} x^{5} y^{3} y^{8}$

Use the product rule: $x^{a} x^{b} = x^{a + b}$

$21x^{2 + 5}y^{3+8}$

Simplify 2+5 to 7.

$21x^{7}y^{3+8}$

Simplfiy 3 + 8 to 11.

$21x^{7}y^{11}$

4 0

2 years ago

Identify the independent and dependent variables in the situation. Gardeners buy fertilizer according to the size of a lawn.

andre [41]

Answer:

Dependant variables- how much fertiliser depends on the size of the lawn

Independent variables- Gardeners will always buy fertiliser.

Step-by-step explanation:

6 0

2 years ago