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dybincka [34]
3 years ago
11

the 7th grade class plans to collect at least 600 pairs of socks for people in need. so far, 135 pairs have been collected. how

many pairs of socks does the class need to collect over the next 5 days
Mathematics
2 answers:
polet [3.4K]3 years ago
7 0

Answer:

465 Socks.

Step-by-step explanation:

600 - 135 = 465

zheka24 [161]3 years ago
3 0
Considering the fact 135 have already been collected, you just subtract that from 600 and you have 465 left. Hope this helps! c:
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A company with a large fleet of cars wants to study the gasoline usage. They check the gasoline usage for 50 company trips chose
Nookie1986 [14]

Answer:

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

Step-by-step explanation:

Notation and definitions  

n=50 represent the sample size  

\bar X= 27.2 represent the sample mean  

s=5.83 represent the sample standard deviation  

m represent the margin of error  

Confidence =88% or 0.88

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 88% of confidence, our significance level would be given by \alpha=1-0.88=0.12 and \alpha/2 =0.06. The degrees of freedom are given by:  

df=n-1=50-1=49  

We can find the critical values in R using the following formulas:  

qt(0.06,49)

[1] -1.582366

qt(1-0.06,49)

[1] 1.582366

The critical value tc=\pm 1.582366  

Calculate the margin of error (m)  

The margin of error for the sample mean is given by this formula:  

m=t_c \frac{s}{\sqrt{n}}  

m=1.582366 \frac{5.83}{\sqrt{50}}=14.613  

With R we can do this:

m=1.582366*(5.83/sqrt(50))

m

[1] 1.304639

Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_{c} \frac{s}{\sqrt{n}}  

And calculating the limits we got:  

27.02 - 1.582366 \frac{5.83}{\sqrt{50}}=25.715  

27.02 + 1.582366 \frac{5.83}{\sqrt{50}}=28.325

Using R the code is:

lower=27.02-m;lower

[1] 25.71536

upper=27.02+m;upper

[1] 28.32464

The 95% confidence interval is given by (25.71536 ;28.32464)  

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

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fredd [130]

Answer:

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Step-by-step explanation:

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The actual distance between town a and Town B is 64 km. What is the distance on Beth's map? Did you use the graph Or the equatio
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
S_A_V [24]

As far as I can tell, the definition of margin of error involves more than you're given in this exercise (for example, you should know how many people were surveyed, the standard deviation, etc etc).

So, I assume that you're looking for a "simplified" interpretation of the margin of error: the estimate are around 80%, with a margin of 4% up or down.

So, you would be claiming that 80% of people is satisfied, with a margin of uncertainty of 4% (so it can be a minimum of 80-4=76 and a maximum of 80+4=84)

6 0
3 years ago
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