Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
Answer:
Step-by-step explanation:
vertex is 1 units left.
y is always positive.
y=|x+1|
Hope this helps! Because when you would fill in the variables 0=0 which which make the expression too that they’d equal the same.
Answer:
5.25
Step-by-step explanation:
Answer:
Hey there!
3.6+6
9.6
Let me know if this helps :)