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Zina [86]
3 years ago
12

What is always important to do before stating the solutions after solving a radical equation? Why?

Mathematics
1 answer:
Stells [14]3 years ago
4 0

Answer: down there

Step-by-step explanation:

When solving a radical equation, it is important to always check your answer by substituting the value back into the original equation. If you get a true statement, then that value is a solution; if you get a false statement, then that value is not a solution.

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E) 1 cubic centimetres = 1÷1000000 cubic meter. Rewrite in scientific notation​
Lady bird [3.3K]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \: 1 \:  \: cm {}^{3} =  \cfrac{1}{1000000}  \:  \: m {}^{3}

\qquad \sf  \dashrightarrow \: 1 \:  \: cm {}^{3} =  \cfrac{1}{10 {}^{6} }  \:  \: m {}^{3}

\qquad \sf  \dashrightarrow \: 1 \:  \: cm {}^{3} =  {}{10 {}^{ - 6} }  \:  \: m {}^{3}

5 0
2 years ago
Solve the double inequality:<br><br> −3&gt;7x−8&gt;−0.2
Aleonysh [2.5K]

Answer:

No solution.

Step-by-step explanation:

−3> 7x−8 > −0.2

Split this into 2 inequalities:

7x - 8 < -3   Add 8 to both side:

7x < 5

x < 5/7.

and:

7x - 8 > -2   Add 8 to both sides:

7x > 6

x > 6/7.

But x cannot be both less than 5.7 and > 6.7,  so No solution.

8 0
3 years ago
If the value of y varies directly with x, which function represents the relationship between x and y when y= 16/5 and x = 20?​
motikmotik
Orchards Osage palsy buds
8 0
3 years ago
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Given f (x) = x2 + 5x + 6, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?
scoray [572]

We want to get the difference quotient for the given function, we will get see that the difference quotient is equal to:

f'(x) = 2x + 5

<h3>The difference quotient:</h3>

For a given function f(x), we define the difference quotient as:

\lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

In this case, we have:

f(x) = x^2 + 5x + 6

Replacing that in the difference quotient we get:

\lim_{h \to 0}  \frac{(x + h)^2 + 5*(x + h) + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{x^2 + 2xh + h^2 + 5*x + 5*h + 6 - x^2 - 5x - 6}{h}\\\\\lim_{h \to 0}  \frac{ 2xh + h^2 + 5*h }{h}\\

Now we can cancel the factor h to get:

\lim_{h \to 0}  2x + h + 5 = 2x + 0 + 5 = 2x + 5

So the difference quotient is equal to 2x + 5.

If you want to learn more about difference quotients, you can read:

brainly.com/question/4224465

5 0
3 years ago
NEED HELP ASAP!!! 20 POINTS, 5 STAR REVIEW AND BRAINLIEST TO WHOEVER IS FIRST!
lesya [120]

Answer:

#1 is 30 degrees

#2 is obtuse

#3 is "No rhombuses are rectangles"

#4 is D

#5 is A

Step-by-step explanation:

For #1, we have an angle vertical to 120 degrees which includes a right angle, so we make an equation:

90+x=120

x=30

So angle x is 30 degrees aka. Option A

For #2, obtuse angles have the sum of the square of the side lengths that are less than the square of the hypotenuse. In this case, 6^2+4^2<9^2 or 50<81

For #3, rhombuses have two pairs of congruent sides but no right angles while rectangles have two pairs of congruent sides but they also have right angles.

For #4, they are similar because one of the triangles is dialated by a scale factor of 1.5.

For #5, just think of turning the triangle on its other side, aka. option A

4 0
3 years ago
Read 2 more answers
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