In the table what are the donain and range of the function relating the pressure and volume of an idea
To solve for x:
Move all the terms containing "x" to the left side of the equation. Do this by adding x to both sides.
2x+x=3x. The new equation is:
3x-1/2=3
Now, move all terms not containing "x" to the right side of the equation. Do this by adding 1/2 to both sides.
3x=3+1/2 The new equation is:
3x=3 1/2, or 3.5
The final step is to isolate x. To do so, divide each side by 3.
3x/3 = 3 1/2 /3 The new equation is:
x=1 1/6
Answer:
14
Step-by-step explanation:
Answer:
the volume of the sphere is

Step-by-step explanation:
This problem bothers on the mensuration of solid shapes, sphere and cube.
Given data
Volume of cube v = 64 cubic inches
since we are dealing with a cube the height and the radius of the sphere is same as the sides of the cube,
we know that volume of cube is expressed as



![l= \sqrt[3]{64}](https://tex.z-dn.net/?f=l%3D%20%5Csqrt%5B3%5D%7B64%7D)

also diameter d=length l
Diameter d=
Radius r =
=
= 
Height h=
we know that the volume of a sphere is given by

substituting into the formula we have
