Answer:
Step-by-step explanation:
In a deck of cart, we have:
a = 4 (aces)
t = 4 (three)
j = 4 (jacks)
And the total number of cards in the deck is
n = 52
So, the probability of drawing an ace as first cart is:
At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is
Therefore, the probability of drawing a three at the 2nd draw is
Then, at the third draw, the previous 2 cards are not replaced, so there are now
cards in the deck. So, the probability of drawing a jack is
Therefore, the total probability of drawing an ace, a three and then a jack is:
Answer:
-120 , split it into diferent parts.
Step-by-step explanation:
12 (52) - 12 (62) = ?
12 x 52 = 624
12 x 62 = 744
624 - 744 = -120
Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
Combine like terms so you end up with 10x+2y
Answer:
1) (6,2) (9,2) (3,8) (3,5)
2) (2,-5) (5,-5) (-1,-11) (-1,-8)
Step-by-step explanation:
For the first question, your reflecting over the x-axis into quadrant I, so you just need to make all the coordinates positive. The numbers stay the same - you just get rid of the negative signs. (6,2) (9,2) (3,8) (3,5)
For the second problem, you subtract 4 from the x-value, and 3 from the y-value.
(6,-2) becomes (2,-5)
(9,-2) becomes (5,-5)
(3,-8) becomes (-1,-11)
(3,-5) becomes (-1,-8)
