Question

Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?

Answer 1

Answer:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

${(x - a)}^{2} + {(y - b)}^{2} = {r}^{2}$

From the question, the center of the circle is located at (-6,2) and the radius is

$r = \sqrt{10}$

We substitute the center and radius to get:

${(x - - 6)}^{2} + {(y - 2)}^{2} = {( \sqrt{10} })^{2}$

Simplify to obtain:

${(x + 6)}^{2} + {(y - 2)}^{2}=10$