Help please? It involves functions

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:NO, NO, YES

Step-by-step explanation:

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Your test scores for the semester are 87,84 and 85.Can you raise your test average to 90 with you next test?

Rainbow [258]

Answer:

Yes

Step-by-step explanation:

If you add 87.84, 85, and 100 you get 272.84. Once you divide that by 3 you get 90.946, which would be your test average if you score 100 on your next test.

6 0

3 years ago

Write an equation in point-slope form of a line that goes through the points (1,4) and (3,-10). Do not use any spaces in your an

olasank [31]

Answer:

y-4=-7(x-1) OR y-(-10)=-7(x-3)

Step-by-step explanation: The point-slope form is $y_$ - $y_{1}$ = $m_$ ( $x_$ - $x_{1}$ )

In slope-intercept form, the equation would be y = -7x + 11

You could find the slope by using the slope equation, $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ .

Using that, you would get -7. Thus by inserting one of the points and the slope in the point-slope equation, you will get your answer.

6 0

3 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.