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antoniya [11.8K]
3 years ago
10

=. Diego and Priya are each saving money. Diego starts with $80 in his savings account and adds $5

Mathematics
1 answer:
stellarik [79]3 years ago
3 0

Answer:

diego. 80+(5x3)= 95

it isn't priya because 30+(5x3)=45

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sammy [17]

Answer:

3

Step-by-step explanation:

I can see it in the demonstration graph

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4 years ago
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(35 points) answer 5 and 7 only please
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A2+b2=c2 and get your answer

3 0
3 years ago
Write the null and alternative hypotheses in words and then symbols for each of the following situations.
Marrrta [24]

Answer:

A) the hypothesis in words and symbols are;

Null hypothesis: Grades have not improved for most students

Alternative hypothesis: Grades have improved for most students

Null hypothesis; H0: p^ = 0.5

Alternative hypothesis; Ha: p^ > 0.5

B) Null hypothesis: During march madness, employees averaged 15 minutes per day on non - business activities

Alternative hypothesis: During march madness, employees averaged more than 15 minutes per day on non-business activities

Null hypothesis; H0: μ = 15

Alternative hypothesis; Ha: μ > 15

Step-by-step explanation:

A) We are told that they sampled 200 of the students who used their service in the past year and ask them if their grades have improved or declined from the previous year. Thus, there will be a 50% chance of success for their grades to have improved and a 50% chance for it to remain the same.

Thus; p^ = 0.5

So the hypothesis in words and symbols are;

Null hypothesis: Grades have not improved for most students

Alternative hypothesis: Grades have improved for most students

Null hypothesis; H0: p = 0.5

Alternative hypothesis; Ha: p > 0.5

B) We are told that they estimate that on a regular business day employees spend on average 15 minutes of company time checking personal email, making personal phone calls, etc

Also, They also collect data on how much company time employees spend on such non-business activities during March Madness.

The hypotheses in words and symbols are;

Null hypothesis: During march madness, employees averaged 15 minutes per day on non - business activities

Alternative hypothesis: During march madness, employees averaged more than 15 minutes per day on non-business activities

Null hypothesis; H0: μ = 15

Alternative hypothesis; Ha: μ > 15

6 0
3 years ago
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}        

a) P(score between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%

P(20 \leq x \leq 30) = 55.88\%

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36

c) P(mean score of sample is between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%

P(20 \leq x \leq 30) =99.84\%

5 0
4 years ago
Sam has striped and spotted socks in his draw in
mojhsa [17]

Answer:

14 spotted socks

Step-by-step explanation:

Sam has 3 units of striped socks and 6 of them.

Find one unit.

3 units = 6

1 unit = 6 ÷ 3 = 2

Sam has 7 units of spotted socks.

7 units = 2 x 7 = 14

7 0
3 years ago
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