Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
This shape is a Rectangle because the sides aren’t even
Answer:
, D
Step-by-step explanation:
3 if x is greater than or equal to 1 is nothing. That leaves us with
if x<1. If you substitute in 1 for x, you get 3, but of course that isn't possible, so the range is
, which is D.
Answer:
Step-by-step explanation:
add the top of one and the bottom of the other then the top of the other and the bottom of one