Answer:
Step-by-step explanation:
Check for continuity by evaluating 2^x and -x^2 - 4x + 1 at the break point x = 0: 2^0 is 1 and -x^2 - 4x + 1 is also 1, so these two functions approach the same value as x approaches 0.
Now do the same thing with
-x^2 - 4x + 1 and (1/2)x + 3 at x = 2; the first comes out to -11 and the second to 4. Thus, this function is not continuous at x = 2.
We must reject statement A.
Statement B: as x increases without bound, (1/2)x + 3 also increases without bound. This statement is true.
Statement C: False, because the quadratic -x^2 - 4x + 1 has a maximum at
x = -b/[2a], or x = -(-4)/[-2], or x = -2
Statement D: True: there are no limitations on the values of the input, x.
