Question

Consider function f.

Answer 1

Answer:

Step-by-step explanation:

Check for continuity by evaluating 2^x and -x^2 - 4x + 1 at the break point x = 0:  2^0 is 1 and -x^2 - 4x + 1 is also 1, so these two functions approach the same value as x approaches 0.

Now do the same thing with

-x^2 - 4x + 1 and (1/2)x + 3 at x = 2; the first comes out to -11 and the second to 4.  Thus, this function is not continuous at x = 2.  

We must reject statement A.

Statement B:  as x increases without bound, (1/2)x + 3 also increases without bound.  This statement is true.

Statement C:  False, because the quadratic -x^2 - 4x + 1 has a maximum at

x = -b/[2a], or x = -(-4)/[-2], or x = -2

Statement D:  True:  there are no limitations on the values of the input, x.

Answer 2

Answer:

B

Step-by-step explanation: