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Arisa [49]
3 years ago
15

If h=2f/m+1 , solve the equation for F. Plz SHOW WORK!!!!

Mathematics
2 answers:
jeyben [28]3 years ago
8 0
h =  \frac{2f}{m} + 1 \\ \\ mh = 2f + 1  (re-arranged) \\ \\ mh - 1 = 2f \\ \\ f =   \frac{(mh - 1)}{2}
MArishka [77]3 years ago
7 0
H=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)
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three students ordered wings that cost $21 and french fries for 6$. If they split the bill equally how much did each student pay
SVEN [57.7K]

The total is $21 + $6 or $27.


There are 3 students.


Let p = how much each student will pay


p = $27 ÷ 3 students


p = $9


Each student will pay $9.


7 0
2 years ago
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What is the result of (x^2 – 10x) – (–5x^2 + x)?
Tanzania [10]

Answer:

( {x}^{2}  - 10x) - ( - 5 {x}^{2}  + x) \\  {x}^{2}  - 10x + 5 {x}^{2}  - x \\  \boxed{6 {x}^{2}  - 11x}

<h3>(6x²-11x) is the right answer.</h3>
6 0
3 years ago
Could you help me to solve the problem below the cost for producing x items is 50x+300 and the revenue for selling x items is 90
s344n2d4d5 [400]

Answer:

Profit function: P(x) = -0.5x^2 + 40x - 300

profit of $50: x = 10 and x = 70

NOT possible to make a profit of $2,500, because maximum profit is $500

Step-by-step explanation:

(Assuming the correct revenue function is 90x−0.5x^2)

The cost function is given by:

C(x) = 50x + 300

And the revenue function is given by:

R(x) = 90x - 0.5x^2

The profit function is given by the revenue minus the cost, so we have:

P(x) = R(x) - C(x)

P(x) = 90x - 0.5x^2 - 50x - 300

P(x) = -0.5x^2 + 40x - 300

To find the points where the profit is $50, we use P(x) = 50 and then find the values of x:

50 = -0.5x^2 + 40x - 300

-0.5x^2 + 40x - 350 = 0

x^2 - 80x + 700 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-80)^2 - 4*700 = 3600

x_1 = (-b + \sqrt{\Delta})/2a = (80 + 60)/2 = 70

x_2 = (-b - \sqrt{\Delta})/2a = (80 - 60)/2 = 10

So the values of x that give a profit of $50 are x = 10 and x = 70

To find if it's possible to make a profit of $2,500, we need to find the maximum profit, that is, the maximum of the function P(x).

The maximum value of P(x) is in the vertex. The x-coordinate of the vertex is given by:

x_v = -b/2a = 80/2 = 40

Using this value of x, we can find the maximum profit:

P(40) = -0.5(40)^2 + 40*40 - 300 = $500

The maximum profit is $500, so it is NOT possible to make a profit of $2,500.

3 0
3 years ago
Round the number 206.8 to the underline place the 0 is underlined
lara [203]

Answer:

210.0

Step-by-step explanation:

you are rounding to the tens place so you look at the number before it is greater than 5 so you round up getting your answer of 210.0

8 0
2 years ago
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M=30/22,5=1,33
m=25/x=1,33. ...>x=25/1,33=18,7
5 0
2 years ago
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