Answer:
Area of the rectangular park = 2/3 square mile
Let us assume the width of the rectangular park = x
Then
The length of the rectangular park = 2 2/3 * x mile
= 8x/3 mile
Then
Area of the rectangular park = Length * Width
2/3 = (8x/3) * x
2/3 = 8x^2/3
(2 * 3)/3 = 8x^2
2 = 8x^2
x^2 = 2/8
x^2 = 1/4
x^2 = (1/2)^2
x = 1/2
So the width of the park is 1/2 feet.
Step-by-step explanation:
Brainliest would be nice
So there is an identity we'll need to use to solve this:
cos(x+y) = cosxcosy - sinxsiny
replace the numerator with the right hand side of that identity and we get:
(cosxcosy - sinxsiny)/cosxsiny
Separate the numerator into 2 fractions and we get:
cosxcosycosxsiny- sinxsiny/cosxsiny
the cosx's cancel on the left fraction, the siny's cancel on the right fraction and we're left with:
cosy/siny - sinx/cosx
which simplifies to:
coty - tanx
Y÷6=29
y=29 x 6
y=174
Hope I can help u
Since they're both already in terms of y, you can just set them equal to each other.
4x = 1/2x + 280
3.5x = 280
x = 80
So 80 would be the amount he needs to sell to make the cost and revenue equal each other.
Sixty nine and seven hundredths
