Min:3
Q1:7.5
Med:10
Q3:13
Max:16
Hope this helps. Have a nice day. Please mark brainliest!
6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
X^2 + 5x = -2
x^2 + 5x + 2 = 0
x = -b (+-) sqrt (b^2 - 4ac) / 2a
a = 1, b = 5, and c = 2
x = -5 (+-) sqrt (5^2 - 4(1)(2)) / 2(1)
x = -5 (+-) sqrt (25 - 8) / 2
x = -5 (+-) sqrt (17) / 2
answer is : negative 5 plus or minus the square root of 17 divided by 2
If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....
J is now (0, -2) multiply by 2
J was (0, -4)
1. 5x+ 2(x+6)
= 5x+ 2x+ 2*6 (distributive property)
= 5x+ 2x+ 12
= (5x+ 2x)+ 12 (combine like terms)
= 7x+ 12
The correct answer is C. 7x+12~
2. <span> -3m + 3(m + 6)
= -3m+ 3m+ 3*6
= -3m+ 3m+ 18
= (-3m+ 3m)+ 18
= 18
The correct answer is D. 18~</span>
