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zloy xaker [14]
3 years ago
7

Help please, 30 points reward, i literally have no clue

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.

If we apply this same process to our picture, we see that the line segment AB' crosses the line \ell at the point (1, 1)

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2a)  -2

b) 8

Step-by-step explanation:

<u>Equation of a parabola in vertex form</u>

f(x) = a(x - h)² + k

where (h, k) is the vertex and the axis of symmetry is x = h

2 a)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is 6, then

                 f(6) = 0

⇒ a(6 - 2)² - 6 = 0

⇒         16a - 6 = 0

⇒              16a = 6

⇒                  a = 6/16 = 3/8

So f(x) = 3/8(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒ 3/8(x - 2)² - 6 = 0

⇒      3/8(x - 2)² = 6

⇒           (x - 2)² = 16

⇒              x - 2 = ±4

⇒                   x = 6,  -2

Therefore, the other x-axis intercept is -2

b)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is -4, then

                 f(-4) = 0

⇒ a(-4 - 2)² - 6 = 0

⇒         36a - 6 = 0

⇒              36a = 6

⇒                  a = 6/36 = 1/6

So f(x) = 1/6(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒  1/6(x - 2)² - 6 = 0

⇒       1/6(x - 2)² = 6

⇒           (x - 2)² = 36

⇒              x - 2 = ±6

⇒                   x = 8,  -4

Therefore, the other x-axis intercept is 8

8 0
2 years ago
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