Answer:
( x+2)^2 + (y+5)^2 = 1
Step-by-step explanation:
The equation of a circle can be written in the form
( x-h)^2 + (y-k)^2 = r^2
where ( h,k) is the center and r is the radius
( x- -2)^2 + (y- -5)^2 = 1^2
( x+2)^2 + (y+5)^2 = 1
The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0.
<h3>What is an algebraic factor?</h3>
An algebraic factor is the multiplication of two algebraic terms.
The root of the quadratic equation formed by the algebraic factor is always real.
That term could be in form of summation multiplication or in subtraction.
As per the given quadratic equation,
3n²+5n+2=0
Let's 5n = 2n + 3n
3n²+ (3n + 2n) + 2 = 0
3n² + 3n + 2n + 2 = 0
(3n² + 3n) + (2n + 2) = 0
3n(n + 1) + 2(n + 1) = 0
(n + 1 )(3n + 2) = 0
Hence "The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0".
For more about the algebraic factor,
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Answer:
D
Step-by-step explanation:
Subtract the exponents
Step-by-step explanation:
step 1
