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fenix001 [56]
4 years ago
7

Hannah just finished building a house of cards that stands four stories high. She is worried that it will fall down. Which of th

e following statements must be true? A. A house of cards is too fragile and must fall down eventually due to gravity. B. If Hannah adds another card to the house of cards, then it will fall down. C. As long as nobody touches the house of cards, it will remain standing. D. If no unbalanced force acts upon the house of cards, then it will remain standing forever.
Chemistry
2 answers:
riadik2000 [5.3K]4 years ago
7 0
I think it's A, a<span> house of cards is too fragile and must fall down eventually due to gravity.



Comment the correct answer. </span>
Burka [1]4 years ago
3 0

the answer is if no unbalanced force acts upon the house of cards then it will remain standing forever.

explanation:Newton's first law of motion states that an object at rest will remain at rest unless acted upon by an unbalanced force.  

Even if nobody touches the house of cards, another type of unbalanced force (like wind) could knock the cards down, or if Hannah adds another card to the house of cards, it may or may not fall down.

However, if no unbalanced force acts upon the house of cards, then it will remain standing forever.

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  • Mass=25g
  • Density=4.93g/cm^3

\\ \rm\rightarrowtail Volume=\dfrac{Mass}{Density}

\\ \rm\rightarrowtail Volume=\dfrac{25}{4.93}

\\ \rm\rightarrowtail Volume=5.1cm^3

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Arrange the following molecules in order of increasing bond polarity (highest bond polarity at the bottom):
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NF3– 0.94– third
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CF4–1.43– fourth

NBr3—NCl3—NF3—CF4
Lowest. Highest
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What power source uses the earth’s internal heat?
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Answer:

Explanation:

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3 years ago
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This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemin
azamat

Answer: your question is incomplete, please let me assume this to be your question.

This application demonstrates how an understanding of free energy can explain seemingly unfavorable reactions proceeding, seemingly, spontaneously. Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions.

ReactionA: P i + glucose ⟶ glucose-6-phosphate + H 2 O Δ G = 13.8 kJ / mol Reaction

ReactionB: P i + fructose-6-phosphate ⟶ fructose-1,6-bisphosphate + H 2 O Δ G = 16.3 kJ / mol

Reaction C: ATP + H 2 O ⟶ ADP + P i Δ G = − 30.5 kJ / mol

1. Which of these reactions is (are) unfavorable? Select all that apply.

2. Which of these reactions can be coupled so that overall reaction is favorable? Select all that apply.

3. What is the net change in free energy if one selection from part (b) is coupled so that the overall reaction is favorable?

THE ANSWERS ARE AS FOLLOWS

1. REACTION B IS UNFAVOURABLE

2. REACTION A AND C CAN BE COUPLED SO THAT OVERALL REACTION IS FAVOURABLE

3. Since reaction b is coupled the net change becomes

13.8+16.3= 30.1

Therefore the net free change becomes

30.5 - 30.1 = 0.4kj/mol

Explanation: The glycolysis pathway

is to describe the oxidation of glucose to pyruvate, with the generation of ATP and NADH. This pathway is also known as the EMBDEN-MEYERHOF PATHWAY.

Reaction B is unfavorable because it is the conversation of glucose into an unstable form, that can be readily cleaved into 3-carbon units. The unfavorable fructose-6-phosphate is quickly consumed to favour the forward reaction.

Reaction A and Reaction C makes the overall reaction to be favoured, since the unfavorable reaction is reaction B, which is an intermediate reaction.

In calculation of net free energy the negative sign which shows Exothermic reaction is multiplied by a negative sign.

The final energy minus the initial energy. The reaction B is added to the initial energy because it is an intermediate reaction, and we were told that one part of it is coupled to the reaction.

Hope this has helped you to solve your question.

5 0
4 years ago
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