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2 years ago

Help please because i am very dumb

Mathematics

1 answer:

Sloan [31]2 years ago

6 0

A) 7000
B) 20000
C) 300000

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Someone help real quick

ValentinkaMS [17]

Answer:

Step-by-step explanation:

From the graph <em>f</em>(-2) = 0

g(-2) = -3(-2) + 2

= 6 + 2 = 8.

So f(-2) is less than g(-2).

2. From the graph the y-intercept of f(x) = 8.

To find the y-intercept of g(x) solve y = -3x +2 when x = 0:

y = -3(0) + 2 = 2.

So f(x) has a greater y-intercept than g().

6 0

2 years ago

How do I do this on a

sergiy2304 [10]

On a what? graph? line?

7 0

3 years ago

15/23 - 5/23<br>lets see who can solve

seraphim [82]

Answer:

10/23

Step-by-step explanation:

15/23 - 5/23 = <u>10/23(Ans)</u>

7 0

2 years ago

Read 2 more answers

Given h(x) = –2 – 3, find h(-6).

igomit [66]

Answer

Step-by-step explanation:

h(-6)=-(-6)-3

h(-6)=6-3

h(-6)=3

4 0

3 years ago

Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.

marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

${a^m} \cdot {a^n} = a^{(m+n)}$

$\dfrac{a^m}{a^n} = a^{(m-n)}$

$\sqrt[m]{a^n} = a^{\frac{n}{m}}$

$(a^m)^n = a^{m\times n}$

$(m\times n)^a = m^a\times n^a$

The expression can be written as $x^9\sqrt[3]{y}$ .

Given to us

$(x^{27}y)^\frac{1}{3}$

$(x^{27}y)^\frac{1}{3}$

Using the exponential property $(m\times n)^a = m^a\times n^a$ ,

$=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}$

Using the exponential property $\sqrt[m]{a^n} = a^{\frac{n}{m}}$ ,

$=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}$

Hence, the expression can be written as $x^9\sqrt[3]{y}$ .

Learn more about Exponent properties:

brainly.com/question/1807508

5 0

1 year ago

Read 2 more answers