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3 years ago

Can someone please help me :,)

Mathematics

1 answer:

ddd [48]3 years ago

5 0

Answer:

The answer is 40

Step-by-step explanation:

8+3+5+4=20

Once you added all the nunbers mutilpy by 2

20x2=40

that's how you get 40 as your answer

hope that helps ❤

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A line has a slope of zero and passes through the point (-2, 3). Which of the following points must also lie on the line? (-2, 5

igomit [66]

Answer:

The answer is B ---> (5,3)

Step-by-step explanation:

If a line has a slope of zero, then it is just a flat horizontal line. So, a point a that line will be the one with the same y-coordinate. Option B is the only option with a y-coordinate that matches the point in the question.

Have a good day

7 0

3 years ago

Read 2 more answers

The vertices of an isosceles triangle are A (-10, 1), B (-6, 3) and C (-4, 7).

adelina 88 [10]

check the picture below.

so, those are the points, now, the line of symmetry, the red one, is the line that will cut the vertex is half and will be perpendicular to the opposite side.

now, the slope of the black line we can just get it off the grid, notice the rise and run, rise/run = 6/6 = 1.

now a perpendicular line to that one will have a negative reciprocal slope, thus

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{1\implies \cfrac{1}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{1}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{1}\implies -1}}$

so the slope of that perpendicular line will be -1, so we're really looking for the equation of a line whose slope is -1 and runs through -6,3.

$\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad \qquad \qquad slope = m\implies -1 \\\\\\ \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=-1[x-(-6)] \\\\\\ y-3=-1(x+6)\implies y-3=-x-6\implies y=-x-3$

5 0

3 years ago

Answer for a lot of points!

earnstyle [38]

Given :

ZC = 90°

CD is the altitude to AB.

$\angle$ A = 65°.

To find :

the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> $\angle$ CAB = 65°.

So,

=> $\angle$ ACB + $\angle$ CAB+ $\angle$ ZCBA = 180° (By angle sum Property.)

=> 90° + 65° + $\angle$ CBA = 180°

=> 155° + $\angle$ CBA = 180°

=> $\angle$ CBA = 180° - 155°

=> $\angle$ CBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> $\angle$ CDB = 90°

=> $\angle$ CBD = $\angle$ CBA = 25°.

So,

=> $\angle$ CBD + $\angle$ DCB = 180° (Angle sum Property.)

=> 90° +25° + $\angle$ DCB = 180°

=> 115° + $\angle$ DCB = 180°

=> $\angle$ DCB = 180° - 115°

=> $\angle$ DCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> $\angle$ ADC = 90°

=> $\angle$ CAD = $\angle$ CAB = 65°.

So,

=> $\angle$ ADC + $\angle$ CAD + $\angle$ DCA = 180° (Angle sum Property.)

=> 90° + 65° + $\angle$ DCA = 180°

=> 155° + $\angle$ DCA = 180°

=> $\angle$ DCA = 180° - 155°

=> $\angle$ DCA = 25°

Hence, we get,

$\angle$ DCA = 25°
$\angle$ DCB = 65°
$\angle$ CDB = 90°
$\angle$ ACD = 25°
$\angle$ ADC = 90°.

7 0

3 years ago

The ratio of the number of boys to the number of girls in a school is 5 : 7. If there are 600 students in the school, how many a

enot [183]

Answer:

350 of the students are girls.

Step-by-step explanation:

5+7 = 12

600/12 = 50

50 x 7 = 350

4 0

3 years ago

Complete the following.

Gnom [1K]

Answer:

Step-by-step explanation:

1) From the given right angle triangle,

22 represents the hypotenuse of the right angle triangle.

With m∠21 as the reference angle,

x represents the opposite side of the right angle triangle.

To determine x, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 21 = x/22

x = 22 Sin 21 = 22 × 0.3584

x = 7.9

2) From the given right angle triangle,

RS represents the hypotenuse of the right angle triangle.

With m∠S as the reference angle,

x represents the adjacent side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 33 = x/15

x = 15 Cos 33 = 15 × 0.8387

x = 12.6

3) From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠A as the reference angle,

x represents the adjacent side of the right angle triangle.

y represents the opposite side of the right angle triangle.

To determine x, we would apply

the Cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 32 = x/10

x = 10 Cos 32 = 10 × 0.848

x = 8.5

To determine y, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 32 = y/10

y = 10 Sin 32 = 10 × 0.5299

y = 0.53

5 0

3 years ago

Can someone please help me :,) ​

Can someone please help me :,)