Answer:
50 degrees
Step-by-step explanation:
We know that an inscribed angle in a circle is 1/2 the arc that it inscribes. So, therefore the arc is inscribed by the 25 degrees is 50. Assuming that the center of the circle is O, the center angle will be the arc measure. Knowing this, angle a is 50 degrees. If you're curious about all these theorems, they can be proved using similar triangles.
fyi, using the same logic, angle b is 25 degrees
Answer:
38.60mm
Step-by-step explanation:
Step one:
Given data
We are given that the dimension of the triangles are length 23 mm and 31 mm
Let us assume that the triangle is a right angle triangle
Step two:
Applying the Pythagoras theorem we can find the third as
square both sides
z= √ 1490
z= 38.60mm
Hence a possible dimension of the third side is 38.60mm
Answer:
∠ACB = 38°
Step-by-step explanation:
∠ACB is an inscribed angle while arcAB is its intercepted arc
An inscribed angle is equal to half the length of its intercepted arc
Hence, ∠ACB = 1/2 the measure of arc AB
arc AB = 76°
Hence ∠ACB = 1/2 of 76
76/2 = 38
Therefore ∠ACB = 38°
Answer:
X = 30°, y = 15° and z = 150°.
Reason: Look below.
Step-by-step explanation:
Hey there!
When we look into the figure, we find that;
For x:
x+ 2x + 90° = 180° {Being linear pair}
or, 3x = 180°-90°
or, 3x = 90°
or, x= 90°/3
<u>Therefore, X = 30°.</u>
For y :
2y = x = 30° {Alternate angles are equal}
or, 2y = 30°
y = 30°/2
<u>Therefore, y = </u><u>1</u><u>5</u><u>°</u>
For z:
2y + z = 180° { Being linear pair}
or, 30°+z = 180°
or, z = 180°-30°
or, z = 150°
<u>Therefore, z = 150°.</u>
<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
A
Step-by-step explanation:
Since m∠JOK is 1/5th of the measure of the full circle (we know this because 72° is 1/5th of 360° and 360° is the measure of the whole circle), we know that the measure of minor arc JK will be 1/5th of the circumference of the circle. C = 2πr and we know that r = 5 so the circumference is 10π. 1/5th of that is 2π.
