What do you get when you cross a monastery with a lion

If male and female college students work an average of 15 hours per week during the school year and the standard deviation is 5.

ki77a [65]

The variance of hours males spend working is almost two times as large as females. 60% of those females are more likely to work between 12.7 to 17.3 hours while 60% of the males work between 9.6 to 20.3 hours based on one standard deviation.

3 0

3 years ago

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If 6/7 of 28 is divided by 2/9 of 21, what is the quotient?

Alja [10]

Answer: 5.150

Step-by-step explanation:

1. Multiply 28 by 6/7

2. Multiply 21 by 2/9

3. Divide 24 by 4.66

6 0

1 year ago

Plzzz help its a math question

Step2247 [10]

Ur answer is -4......

7 0

3 years ago

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2. A marketing firm is trying to estimate the proportion of potential car buyers that would consider

Maurinko [17]

Answer:

a. The number of people that should be in the pilot study are 600 people

b. The point estimate is 0.62 $\overline 6$

c. At 95% confidence level the true population proportion of potential car buyers of hybrid vehicle is between the confidence interval (0.588, 0.6654)

d. Two ways to reduce the margin of error are;

1) Reduce the confidence interval

2) Use a larger sample size

Step-by-step explanation:

a. The given parameters for the estimation of sample size is given as follows;

The margin of error for the confidence interval, E = 4% = 0.04

The confidence level = 95%

The sample size formula for a proportion as obtained from an online source is given as follows;

$n = \dfrac{Z^2 \times P \times (1 - P)}{E^2}$

Where, P is the estimated proportions of the desired statistic, therefore, we have for a new study, P = 0.5;

Z = The level of confidence at 95% = 1.96

n + The sample size

Therefore, we have;

$n = \dfrac{1.96^2 \times 0.5 \times (1 - 0.5)}{0.04^2} = 600.25$

Therefore, the number of people that should be in the pilot study in order to meet this goal at 95% confidence level is n = 600 people

b. The point estimate for the population proportion is the sample proportion given as follows;

$\hat p = \dfrac{x}{n}$

Where;

x = The number of the statistic in the sample

n = The sample size

From the question, we have;

The number of potential car buyers, n = 600

The number of respondent in the sample that indicated that they would consider purchasing a hybrid, x = 376

Therefore, the point estimate, for the proportion of potential car buyers that would consider buying a hybrid vehicle, $\hat p$ = 376/600 = 0.62 $\overline 6$