F and D is the answer
hope this helps
have a good day
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
A-is farthest to the right on the number line
B-in the middle of the number line
C- farthest to the left on the number line
Step-by-explanation
If we have 3 random numbers we can conclude that a<c so we can say
A is farthest to the right
B in the middle
C: farthest to the left.
180 miles? seems like the question is incomplete
