Let x = Class A
Let y = Class B
Let z = Class C
Equations from problem:
x - 160 = y
2/3x = z
y + 92 = z
Solving through substitution:
2/3x = y + 92
2/3x = (x - 160) + 92
2/3x = x - 68
-1/3x = -68
3(-1/3x) = 3(-68)
-x = -204
x = 204
Now substitute x in the first equation to get y:
204 - 160 = y
44 = y
44 = Class B
There are 44 folded paper cranes in Class B.
Answer: x=-2 y=2
Step-by-step explanation:
I decided that isolating the y value of the second equation is the best way to start solving.
I divide 3 from both sides to get y= (4-x)/3. With this, I can substitute into the first equation. 4x+3(4-x)/3)=-2.
The multiplying the 3 by the denominator three cancels each other out to make:
4x+4-x=-2.
We subtract 4 on both sides and then subtract x from 4x.
We end up with 3x=-6. Then, we divide both sides by 3.
x=-2.
Now we substitute this into the second equation to solve.
3y=4-(-2)
This becomes 3y=4+2 which is 3y=6
We divide both sides by 3 to get y=2
We end up with x=-2 and y=2.
I hope you learned something :)
Answer:
8 bags at the orchard
Step-by-step explanation:
6/25 = .24
8/35 = .22
Answer:
it is possible to get something rational.
Step-by-step explanation:
This can't really be explained.
